3.正确输出由高到低的分数顺序
生成了文本文件file.3dat
里面的数据正确并且直观可读
4.正确输出由高到低排列的学生信息
生成了二进制文件
数据不能直观读出
#include <stdio.h> #include <stdlib.h> #define N 10 typedef struct student { int num; char name[20]; int score; }STU; int main() { FILE *fin; STU st[N]; int i; fin = fopen("file4.dat","rb"); if( !fin ) { printf("fail to open file4.dat\n"); exit(0); } fread(st,sizeof(STU),N,fin); fclose(fin); for(i=0; i<N; i++) printf("%-6d%-10s%3d\n", st[i].num, st[i].name, st[i].score); return 0; }
#include <stdio.h> #include <string.h> #include <stdlib.h> const int N = 10; typedef struct student { long int id; char name[20]; float objective; float subjective; float sum; char level[10]; }STU; void input(STU s[], int n); void output(STU s[], int n); void process(STU s[], int n); int main() { STU stu[N]; printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N); input(stu, N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu, N); printf("\n打印考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级\n"); output(stu, N); return 0; } void input(STU s[], int n) { FILE *fin; int i; fin=fopen("examinee.txt","r"); if(!fin){ printf("fail to open examinee.txt\n"); exit(0); } for(i=0;i<n;i++) fscanf(fin,"%ld %s %f %f",&s[i].id,s[i].name,&s[i].objective,&s[i].subjective); fclose(fin); } void output(STU s[], int n) { FILE *fout; int i; fout=fopen("result.txt","w"); if(!fout){ printf("fail to open result.txt\n"); exit(0); } for(i=0;i<N;i++) fprintf(fout,"%6ld %8s %7.2f %11.2f %9.2f %4s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); fwrite(s,sizeof(STU),n,fout); fclose(fout); printf("\n准考证号 姓名 客观题得分 操作题得分 总分 等级\n"); for(i=0;i<N;i++) printf("%6ld %8s %7.2f %11.2f %9.2f %4s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); } void process(STU s[], int n) { int i,j; STU temp; for(i=0;i<n;i++) s[i].sum=s[i].objective+s[i].subjective; for(i=0;i<n-1;i++) for(j=0;j<n-1-i;j++) if(s[j].sum<s[j+1].sum) { temp = s[j]; s[j] = s[j+1]; s[j+1] = temp; } for(i=0;i<n;i++) { if(i+1<=n*0.1) strcpy(s[i].level,"优秀"); if(i+1>n*0.1&&i+1<=n*0.5) strcpy(s[i].level,"合格"); if(i+1>n*0.5&&i+1<=n) strcpy(s[i].level,"不合格"); } }