任务三:由高到低的分数顺序正确输出
生成了文本文件file.3dat
数据正确并且可读
任务四:由高到低排列的学生信息正确输出
生成了二进制文件
数据不能读出
#include <stdio.h> #include <stdlib.h> #define N 10 typedef struct student { int num; char name[20]; int score; }STU; int main() { FILE *fin; STU st[N]; int i; fin = fopen("file4.dat","rb"); if( !fin ) { printf("fail to open file4.dat\n"); exit(0); } fread(st,sizeof(STU),N,fin); fclose(fin); for(i=0; i<N; i++) printf("%-6d%-10s%3d\n", st[i].num, st[i].name, st[i].score); return 0; }
#include <stdio.h> #include <stdlib.h> #include <string.h> const int N=10; typedef struct student{ long int id; char name[20]; float objective; float subjective; float sum; char level[10]; }STU; void input(STU s[],int n); void output(STU s[],int n); void process(STU s[],int n); int main(){ STU stu[N]; printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n",N); input(stu,N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu,N); printf("\n打印考生完整信息:准考证号,姓名,客观题得分,操作题得分,总分,等级\n"); output(stu,N); return 0; } void input(STU s[],int n){ FILE *fp; int i; fp=fopen("examinee.txt","r"); if(!fp){ printf("fail to open examinee.txt\n"); exit(0); } for(i=0;i<N;i++) fscanf(fp,"%ld %s %f %f",&s[i].id,s[i].name,&s[i].objective,&s[i].subjective); fclose(fp); } void output(STU s[],int n){ FILE *fp; int i; fp=fopen("result.txt","w"); if(!fp){ printf("fail to open result.txt\n"); exit(0); } for(i=0;i<N;i++) fprintf(fp,"%6ld %8s %7.2f %11.2f %9.2f %4s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); fclose(fp); printf("\n准考证号 姓名 客观题得分 操作题得分 总分 等级\n"); for(i=0;i<N;i++) printf("%6ld %8s %7.2f %11.2f %9.2f %4s\n",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level); } void process(STU s[],int n){ STU m; int i,j; for(i=0;i<n;i++) s[i].sum=s[i].objective+s[i].subjective; for(i=0;i<n-1;i++) for(j=i+1;j<n;j++) if(s[i].sum<s[j].sum){ m=s[i]; s[i]=s[j]; s[j]=m; } char a[3][10]={"优秀","合格","不合格"}; for(i=0;i<n;i++){ if(i+1<=n/10) strcpy(s[i].level,a[0]); else if(i+1>n/10&&i<=n/2) strcpy(s[i].level,a[1]); else strcpy(s[i].level,a[2]); } }