Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.

+---------+------------+------------------+

| Id(INT) | Date(DATE) | Temperature(INT) |

+---------+------------+------------------+

|       1 | 2015-01-01 |               10 |

|       2 | 2015-01-02 |               25 |

|       3 | 2015-01-03 |               20 |

|       4 | 2015-01-04 |               30 |

+---------+------------+------------------+

For example, return the following Ids for the above Weather table:

+----+

| Id |

+----+

|  2 |

|  4 |

+----+

 # Write your MySQL query statement below

 select w1.Id

 from Weather w1,Weather w2

 where datediff(w1.Date,w2.Date)=1

 and w1.Temperature>w2.Temperature;