2019 牛客多校第六场 J Upgrading Technology

题目链接:https://ac.nowcoder.com/acm/contest/886/J

题目大意

  略。

分析

  见代码。

代码如下

2019 牛客多校第六场 J Upgrading Technology
  1 #include <bits/stdc++.h>
  2 using namespace std;
  3  
  4 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
  5 #define Rep(i,n) for (int i = 0; i < (n); ++i)
  6 #define For(i,s,t) for (int i = (s); i <= (t); ++i)
  7 #define rFor(i,t,s) for (int i = (t); i >= (s); --i)
  8 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i)
  9 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i)
 10 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i)
 11 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i)
 12  
 13 #define pr(x) cout << #x << " = " << x << "  "
 14 #define prln(x) cout << #x << " = " << x << endl
 15  
 16 #define LOWBIT(x) ((x)&(-x))
 17  
 18 #define ALL(x) x.begin(),x.end()
 19 #define INS(x) inserter(x,x.begin())
 20 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end())
 21 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // ?? x ?????? c 
 22 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower);
 23 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper);
 24  
 25 #define ms0(a) memset(a,0,sizeof(a))
 26 #define msI(a) memset(a,inf,sizeof(a))
 27 #define msM(a) memset(a,-1,sizeof(a))
 28 
 29 #define MP make_pair
 30 #define PB push_back
 31 #define ft first
 32 #define sd second
 33  
 34 template<typename T1, typename T2>
 35 istream &operator>>(istream &in, pair<T1, T2> &p) {
 36     in >> p.first >> p.second;
 37     return in;
 38 }
 39  
 40 template<typename T>
 41 istream &operator>>(istream &in, vector<T> &v) {
 42     for (auto &x: v)
 43         in >> x;
 44     return in;
 45 }
 46 
 47 template<typename T>
 48 ostream &operator<<(ostream &out, vector<T> &v) {
 49     Rep(i, v.size()) out << v[i] << " \n"[i == v.size()];
 50     return out;
 51 }
 52 
 53 template<typename T1, typename T2>
 54 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) {
 55     out << "[" << p.first << ", " << p.second << "]" << "\n";
 56     return out;
 57 }
 58 
 59 inline int gc(){
 60     static const int BUF = 1e7;
 61     static char buf[BUF], *bg = buf + BUF, *ed = bg;
 62     
 63     if(bg == ed) fread(bg = buf, 1, BUF, stdin);
 64     return *bg++;
 65 } 
 66 
 67 inline int ri(){
 68     int x = 0, f = 1, c = gc();
 69     for(; c<48||c>57; f = c=='-'?-1:f, c=gc());
 70     for(; c>47&&c<58; x = x*10 + c - 48, c=gc());
 71     return x*f;
 72 }
 73 
 74 template<class T>
 75 inline string toString(T x) {
 76     ostringstream sout;
 77     sout << x;
 78     return sout.str();
 79 }
 80 
 81 inline int toInt(string s) {
 82     int v;
 83     istringstream sin(s);
 84     sin >> v;
 85     return v;
 86 }
 87 
 88 //min <= aim <= max
 89 template<typename T>
 90 inline bool BETWEEN(const T aim, const T min, const T max) {
 91     return min <= aim && aim <= max;
 92 }
 93  
 94 typedef long long LL;
 95 typedef unsigned long long uLL;
 96 typedef pair< double, double > PDD;
 97 typedef pair< int, int > PII;
 98 typedef pair< int, PII > PIPII;
 99 typedef pair< string, int > PSI;
100 typedef pair< int, PSI > PIPSI;
101 typedef set< int > SI;
102 typedef set< PII > SPII;
103 typedef vector< int > VI;
104 typedef vector< double > VD;
105 typedef vector< VI > VVI;
106 typedef vector< SI > VSI;
107 typedef vector< PII > VPII;
108 typedef map< int, int > MII;
109 typedef map< int, string > MIS;
110 typedef map< int, PII > MIPII;
111 typedef map< PII, int > MPIII;
112 typedef map< string, int > MSI;
113 typedef map< string, string > MSS;
114 typedef map< PII, string > MPIIS;
115 typedef map< PII, PII > MPIIPII;
116 typedef multimap< int, int > MMII;
117 typedef multimap< string, int > MMSI;
118 //typedef unordered_map< int, int > uMII;
119 typedef pair< LL, LL > PLL;
120 typedef vector< LL > VL;
121 typedef vector< VL > VVL;
122 typedef priority_queue< int > PQIMax;
123 typedef priority_queue< int, VI, greater< int > > PQIMin;
124 const double EPS = 1e-8;
125 const LL inf = 0x7fffffff;
126 const LL infLL = 0x7fffffffffffffffLL;
127 const LL mod = 1e9 + 7;
128 const int maxN = 1e3 + 7;
129 const LL ONE = 1;
130 const LL evenBits = 0xaaaaaaaaaaaaaaaa;
131 const LL oddBits = 0x5555555555555555;
132 
133 int T, N, M, c[maxN][maxN], d[maxN];
134 LL ans;
135 // dp[i][j]表示 i 号武器,从等级 j - 1开始能获得的最大收益 
136 // dp[i][j] = max(dp[i][j + 1] + c[i][j - 1], 0)
137 LL dp[maxN][maxN];
138 
139 // preSum[i] 表示所有武器升到 i 级所能获得的基础分 
140 LL preSum[maxN];
141 
142 int main(){
143     //freopen("MyOutput.txt","w",stdout);
144     //freopen("input.txt","r",stdin);
145     INIT();
146     cin >> T;
147     For(cases, 1, T) {
148         ans = 0;
149         ms0(preSum);
150         
151         cin >> N >> M;
152         For(i, 1, N) {
153             For(j, 1, M) {
154                 cin >> c[i][j];
155                 c[i][j] = -c[i][j];
156                 preSum[j] += c[i][j];
157             }
158             dp[i][M] = max(0, c[i][M]);
159         }
160         
161         For(j, 1, M) {
162             cin >> d[j];
163             preSum[j] += d[j] + preSum[j - 1];
164         }
165         
166         For(i, 1, N) {
167             rFor(j, M - 1, 1) {
168                 dp[i][j] = max((LL)0, c[i][j] + dp[i][j + 1]);
169             }
170         }
171         
172         // 枚举所有武器最低等级 
173         For(j, 0, M) {
174             LL sum = preSum[j], minS = infLL;
175             
176             For(i, 1, N) {
177                 sum += dp[i][j + 1];
178                 minS = min(minS, dp[i][j + 1]);
179             } 
180             sum -= minS; // 让收益最低的武器成为短板 
181             
182             ans = max(ans, sum);
183         }
184         
185         cout << "Case #" << cases << ": " << ans << endl;
186     }
187     return 0;
188 }
View Code

 

上一篇:使用Proguard发行的Android App崩溃


下一篇:nginx 反向代理及 https 证书配置