1015 德才论 (25分)

 

 

输入样例：

14 60 80
10000001 64 90
10000002 90 60
10000011 85 80
10000003 85 80
10000004 80 85
10000005 82 77
10000006 83 76
10000007 90 78
10000008 75 79
10000009 59 90
10000010 88 45
10000012 80 100
10000013 90 99
10000014 66 60

 

输出样例：

12
10000013 90 99
10000012 80 100
10000003 85 80
10000011 85 80
10000004 80 85
10000007 90 78
10000006 83 76
10000005 82 77
10000002 90 60
10000014 66 60
10000008 75 79
10000001 64 90

思路：
1.按题目要求分四类人
2.同类人分高在前，同类同分德分高在前，同类同分同德按准考证降序

要特别注意:
1.题目给的及格优秀线60和80要求输入给出，是变量，不要直接设置为60和80
2.可能会导致测试点234错误的地方（看代码）

首次通过代码:

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #include<string.h>
 4 int score1,score2;
 5 struct student{
 6     char id[9];
 7     int d_score;
 8     int c_score;
 9 };
10 
11 int judge(struct student s1){
12     if(s1.d_score>=score2&&s1.c_score>=score2) return 1;
13     else if(s1.d_score>=score2) return 2;
14     else if(s1.d_score<score2&&s1.c_score<score2&&s1.d_score>=s1.c_score) return 3;
15     else return 4;
16 }
17 
18 int cmp(const void *a,const void *b){
19     struct student a1=*(struct student*)a;
20     struct student b1=*(struct student*)b;
21     int r1=judge(a1),r2=judge(b1);
22     int sum1=a1.d_score+a1.c_score;
23     int sum2=b1.d_score+b1.c_score;
24     if(r1<r2) return -1;
25     else if(r1==r2){
26         if(sum1>sum2) return -1;
27         else if(sum1==sum2) {
28             if(a1.d_score>b1.d_score) return -1;
29             else if(a1.d_score==b1.d_score) {
30                 return strcmp(a1.id,b1.id);//这里要返回直接返回strcmp(a1.id,b1.id); 因为可能会返回0
31             }
32             else return 1;
33         }
34         else return 1;
35     }
36     else return 1;
37 }
38 
39 int main(){
40   struct student s1[100005];
41   int sum;
42   int num=0;
43   scanf("%d %d %d",&sum,&score1,&score2);
44   for(int i=0;i<sum;i++){
45       struct student s2;
46       scanf("%s %d %d",s2.id,&s2.d_score,&s2.c_score);
47       if(s2.d_score>=score1&&s2.c_score>=score1) s1[num++]=s2;
48   }
49   qsort(s1,num,sizeof(struct student),cmp);
50   printf("%d\n",num);
51   for(int i=0;i<num;i++){
52       printf("%s %d %d",s1[i].id,s1[i].d_score,s1[i].c_score);
53       if(i!=num-1) printf("\n");
54   }
55   return 0;
56 }

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