67. Add Binary
EasyGiven two binary strings, return their sum (also a binary string).
The input strings are both non-empty and contains only characters 1
or 0
.
Example 1:
Input: a = "11", b = "1" Output: "100"
Example 2:
Input: a = "1010", b = "1011" Output: "10101"
package leetcode.easy; public class AddBinary { @org.junit.Test public void test() { String a1 = "11"; String b1 = "1"; String a2 = "1010"; String b2 = "1011"; System.out.println(addBinary(a1, b1)); System.out.println(addBinary(a2, b2)); } public String addBinary(String a, String b) { StringBuffer buffer = new StringBuffer(); int sum = 0; int carry = 0; for (int i = a.length() - 1, j = b.length() - 1; i >= 0 || j >= 0; i--, j--) { sum = carry; if (i >= 0) { sum += a.charAt(i) - '0'; } if (j >= 0) { sum += b.charAt(j) - '0'; } buffer.append(sum % 2); carry = sum / 2; } if (carry != 0) { buffer.append(carry); } return buffer.reverse().toString(); } }