1、新建一个Html页面，命名为Test.html

 <script type="text/javascript" src="easyui/jquery.min.js"></script>

 <script type="text/javascript" src="easyui/jquery.easyui.min.js"></script>

 <script type="text/javascript" src="easyui/locale/easyui-lang-zh_CN.js"></script>

 <script type="text/javascript" src="js/save.js"></script>

 <link rel="stylesheet" type="text/css" href="easyui/themes/default/easyui.css" />

 <link rel="stylesheet" type="text/css" href="easyui/themes/icon.css" />

 　　<div>

 　　　　<input type="text" id="txtFileNames" class="textbox" name="Vassets" style="width:110px;"/>

 　　　　<a href="#" class="easyui-linkbutton" iconCls="icon-search" onclick="objV.saves()">保存</a>

 　　</div>

2、新建一个JS页面，命名为save.js

 objV = {

         saves:function(){

             $.ajax({

                 type: "POST",

                 url: "Test.ashx",

                 contentType: "application/json; charset=utf-8",

                 data: JSON.stringify(GetJsonData()),

                 dataType: "json",

                 success: function (message) {

                     if (message > 0) {

                         alert("请求已提交！我们会尽快与您取得联系");

                     }

                 },

                 error: function (message) {

                     $("#request-process-patent").html("提交数据失败！");

                 }

             });

         }

     };

     function GetJsonData() {

         var json = {

             "FTName": $("#txtFileNames").val()

         };

         return json;

     }

3、新建一个AddTest.ashx页面

 　　　　　　  int num = ;

             context.Response.ContentType = "application/json";

             var data = context.Request;

             var sr = new StreamReader(data.InputStream);

             var stream = sr.ReadToEnd();

             var javaScriptSerializer = new JavaScriptSerializer();

             var PostedData = javaScriptSerializer.Deserialize<Model.FileType>(stream);

             DataAccess<Model.FileType> da = new DataAccess<Model.FileType>();

             try

             {

                 num = da.Add(PostedData, "FileType");

             }

             catch (Exception msg)

             {

                 context.Response.Write(msg.Message);

             }

             context.Response.ContentType = "text/plain";

             context.Response.Write(num);