我有这个物品类：

public class Movie
{
    public string VideoId { get; set; }
    public string Title { get; set; }
}

我有List< Movie>这些项目,我使用以下代码将序列化为xml文件：

string fileName = index + ".xml";
string serializationFile = Path.Combine(dir, fileName);

XmlWriterSettings settings = new XmlWriterSettings();
settings.Indent = true;

using (var writer = XmlWriter.Create(serializationFile, settings))
{
    var serializer = new XmlSerializer(typeof(List<Movie>));
    serializer.Serialize(writer, tmpList);
}

结果如下：

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfMovie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Movie>
    <VideoId>MyId</VideoId>
    <Title>MyTitle</Title>
  </Movie>
  <Movie>
    <VideoId>MyId1</VideoId>
    <Title>MyTitle1</Title>
  </Movie>
  <Movie>
    <VideoId>MyId2</VideoId>
    <Title>MyTitle2</Title>
  </Movie>
  <Movie>
    <VideoId>MyId3</VideoId>
    <Title>MyTitle3</Title>
  </Movie>
</ArrayOfMovie>

这样就可以向ArrayOfMovie节点添加属性,如下所示：

<ArrayOfMovie xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" customattribute='Yes'>

解决方法:

是的,您可以使用XmlAttribute attribute进行此操作.为此,您需要定义自定义属性.它带有一个代表数组的更多类的价格(嵌套在根节点中).如果您对此添加没有任何问题,那么解决方案可以如下所示：

public class ArrayOfMovie
{
    // define the custom attribute
    [XmlAttribute(AttributeName="CustomAttribute")]
    public String Custom { get; set; }
    // define the collection description
    [XmlArray(ElementName="Items")]
    public List<Movie> Items { get; set; }
}

public class Movie
{
    public string VideoId { get; set; }
    public string Title { get; set; }
}

然后像您已经创建的那样创建,填充和序列化-一件事是填充您的自定义属性：

// create and fill the list
var tmpList = new List<Movie>();
tmpList.Add(new Movie { VideoId = "1", Title = "Movie 1" });
tmpList.Add(new Movie { VideoId = "2", Title = "Movie 2" });
// create the collection
var movies = new ArrayOfMovie 
            { 
                Items = tmpList, 
                Custom = "yes" // fill the custom attribute
            };
// serialize
using (var writer = XmlWriter.Create(serializationFile, settings))
{
    var serializer = new XmlSerializer(typeof(ArrayOfMovie));
    serializer.Serialize(writer, movies);
}

XML输出如下所示：

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfMovie   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
                xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
                CustomAttribute="yes">
  <Items>
    <Movie>
      <VideoId>1</VideoId>
      <Title>Movie 1</Title>
    </Movie>
    <Movie>
      <VideoId>2</VideoId>
      <Title>Movie 2</Title>
    </Movie>
  </Items>
</ArrayOfMovie>