https://leetcode.com/problems/reverse-only-letters/
Given a string S
, return the "reversed" string where all characters that are not a letter stay in the same place, and all letters reverse their positions.
Example 1:
Input: "ab-cd" Output: "dc-ba"
Example 2:
Input: "a-bC-dEf-ghIj" Output: "j-Ih-gfE-dCba"
Example 3:
Input: "Test1ng-Leet=code-Q!" Output: "Qedo1ct-eeLg=ntse-T!"
Note:
S.length <= 100
-
33 <= S[i].ASCIIcode <= 122
-
S
doesn't contain\
or"
代码:
class Solution { public: string reverseOnlyLetters(string S) { string ans = ""; vector<char> v; int len = S.length(); for(int i = len - 1; i >= 0; i --) { if(S[i] >= 'a' && S[i] <= 'z' || S[i] >= 'A' && S[i] <= 'Z') v.push_back(S[i]); } int rec = 0; for(int i = 0; i < len; i ++) { if(S[i] >= 'a' && S[i] <= 'z' || S[i] >= 'A' && S[i] <= 'Z') { char c = v[rec]; ans += c; rec ++; } else ans += S[i]; } return ans; } };
FH