我对Java(6/7/8)语法有一个愚蠢的问题-这两个方法调用片段是否总是等效的?
>与此
this.myMethod(4);
>没有这个
myMethod(4);
注意:当然,问题在于参数的每个数字,类型和组合
较弱的说法:给定程序P,我只能删除该程序才能创建程序P’.在每个方法调用的前面?
我已经考虑了本地类,匿名类,内部类和各种继承,但可能没有发现任何矛盾.因此,我相信两个片段实际上都是相同的.不幸的是,我无法找到任何合适的证明(例如,从官方语法中).
您能通过矛盾证明我错了吗,还是给我一些构造等效证明的线索?非常感谢.
编辑:证明等价是错误的(请参见下面的评论)较弱的语句呢?
解决方法:
- If the form is
MethodName
– that is, just anIdentifier
– then:
- Otherwise, let
T
be the enclosing type declaration of which the method is a member, and let n be an integer such thatT
is the n’th
lexically enclosing type declaration of the class whose declaration
immediately contains the method invocation. The target reference is
the n’th lexically enclosing instance ofthis
.
和
When used as a primary expression, the keyword
this
denotes a value
that is a reference to the object for which the instance method or
default method was invoked (§15.12), or to the object being
constructed
和
- If the form is
Primary . [TypeArguments] Identifier
involved, then:
- Otherwise, the Primary expression is evaluated and the result is used as the target reference.
这里主要指此.*.
在两种情况下,该方法都将解析为相同的方法.
给定所有这些信息,就没有可以从可编译程序P创建的可编译程序P’.