404. Sum of Left Leaves
【题目】中文版 英文版
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution
{
public:
int sumOfLeftLeaves(TreeNode* root)
{
int res = ;
solute(root, res, false);
return res;
}
void solute(TreeNode *root, int &sum, bool flag)
{
if(root == nullptr)
return;
if(!root->left && !root->right)
{
if(flag == true)
sum += root->val;
return;
}
solute(root->left, sum, true);
solute(root->right, sum, false);
return;
}
};