dfs(x,y,n)表示长为x,宽为y,切n块
每次砍的一定是x/n的倍数或者y/n的倍数
#include<bits/stdc++.h>
using namespace std;
const int inf=1e9;
int x,y,n;
double dfs(double x,double y,int n)
{
if(n==)return max(x,y)/min(x,y);
double sum=1.0*inf;
double xx=x/n,yy=y/n;
for(int i=;i<=(n>>);i++)
sum=min(sum,max(dfs(xx*i,y,i),dfs(x-xx*i,y,n-i))),
sum=min(sum,max(dfs(x,yy*i,i),dfs(x,y-yy*i,n-i)));
return sum;
}
int main()
{
scanf("%d%d%d",&x,&y,&n);
printf("%.6lf\n",dfs(1.0*x,1.0*y,n));
}