>>> a = [1,2,3,4]
>>> b = [1,2,3,4,5]
>>> c = [1,2,3,4]
>>> cmp(a,b)
-1
>>> cmp(a,c)
0

>>> a
[1, 2, 3, 4]
>>> d = []
>>> for i in a:
...   d.append(i + 2)
...
>>> d
[3, 4, 5, 6]
>>> e = []
>>> e = [i + 2 for i in a]
>>> e
[3, 4, 5, 6]

>>> d = dict.fromkeys(['today','tomorrow'],20)
>>> d
{'tomorrow': 20, 'today': 20}

>>> s = {1,2,3,4}
>>> t = {4,3,6}
>>> s
set([1, 2, 3, 4])
>>> t
set([3, 4, 6])
>>> t | s  # 并集
set([1, 2, 3, 4, 6])
>>> t & s  #交集
set([3, 4])
>>> t - s  #差集 在t中不在s中
set([6])
>>> t ^ s  #对称差集  不在ts同时存在的值
set([1, 2, 6])

    ①map
    >>> a
    [1, 2, 3, 4]
    >>> n = map(lambda x:x+2,a)
    >>> n
    [3, 4, 5, 6]
    #注意：在3.x中需要n = list(n)
    ②reduce
    >>>reduce(lambda x,y:x*y, range(1,8))
    #上述命令相当于
    >>> s = 1
    >>> for i in range(1,8):
    ...   s = s * i
    ...
    >>> s
    5040
    #注意：python3.x 需要from fuctools import reduce
    ③filter
    >>> b = filter(lambda x: x > 5 and x < 8 , range(10))
    >>> b
    [6, 7]

    #上述函数比for和while循环效率高