我有一张桌子如下：

mysql> DESCRIBE student_lectures;
+------------------+----------+------+-----+---------+----------------+
| Field            | Type     | Null | Key | Default | Extra          |
+------------------+----------+------+-----+---------+----------------+
| id               | int(11)  | NO   | PRI | NULL    | auto_increment |
| course_module_id | int(11)  | YES  | MUL | NULL    |                |
| day              | int(11)  | YES  |     | NULL    |                |
| start            | datetime | YES  |     | NULL    |                |
| end              | datetime | YES  |     | NULL    |                |
| cancelled_at     | datetime | YES  |     | NULL    |                |
| lecture_type_id  | int(11)  | YES  |     | NULL    |                |
| lecture_id       | int(11)  | YES  |     | NULL    |                |
| student_id       | int(11)  | YES  |     | NULL    |                |
| created_at       | datetime | YES  |     | NULL    |                |
| updated_at       | datetime | YES  |     | NULL    |                |
+------------------+----------+------+-----+---------+----------------+

我基本上想找到一个讲座没有发生的时间 – 所以为了做到这一点,我正在考虑将重叠讲座分组在一起(例如,上午9点到10点和上午10点到11点,讲座将显示为单上9点至11点的演讲).背靠背可能会有两个以上的讲座.

我现在有这个：

SELECT l.start, l2.end
FROM student_lectures l
LEFT JOIN student_lectures l2 ON ( l2.start = l.end )
WHERE l.student_id = 1 AND l.start >= '2010-04-26 09:00:00' AND l.end <= '2010-04-30 19:00:00' AND l2.end IS NOT NULL AND l2.end != l.start
GROUP BY l.start, l2.end
ORDER BY l.start, l2.start

哪个回报：

+---------------------+---------------------+
| start               | end                 |
+---------------------+---------------------+
| 2010-04-26 09:00:00 | 2010-04-26 11:00:00 |
| 2010-04-26 10:00:00 | 2010-04-26 12:00:00 |
| 2010-04-26 10:00:00 | 2010-04-26 13:00:00 |
| 2010-04-26 13:15:00 | 2010-04-26 16:15:00 |
| 2010-04-26 14:15:00 | 2010-04-26 16:15:00 |
| 2010-04-26 15:15:00 | 2010-04-26 17:15:00 |
| 2010-04-26 16:15:00 | 2010-04-26 18:15:00 |
...etc...

我正在寻找的输出是：

+---------------------+---------------------+
| start               | end                 |
+---------------------+---------------------+
| 2010-04-26 09:00:00 | 2010-04-26 13:00:00 |
| 2010-04-26 13:15:00 | 2010-04-26 18:15:00 |

任何帮助表示感谢,谢谢！

解决方法:

这样的事情应该有效.

SELECT l2.start,l.end
来自student_lectures l
LEFT JOIN student_lectures l2 ON l2.end
在l.start和l.end之间
在哪里.开始
BETWEEN’2010-04-26 00:00:00’和’2010-04-26 23:59:59′
GROUP BY l.start
订购l.start