题目描述：
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive.
Example:
Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1
sumRange(2, 5) -> -1
sumRange(0, 5) -> -3
Note:
- You may assume that the array does not change.
- There are many calls to sumRange function.
解题思路：
如代码所示。
代码如下：
public class NumArray {
int[] nums;
public NumArray(int[] nums) {
for(int i = 1; i < nums.length; i++){
nums[i] += nums[i - 1];
}
this.nums = nums;
}
public int sumRange(int i, int j) {
if(i == 0)
return nums[j];
return nums[j] - nums[i - 1];
}
}
// Your NumArray object will be instantiated and called as such:
// NumArray numArray = new NumArray(nums);
// numArray.sumRange(0, 1);
// numArray.sumRange(1, 2);