这几天终于把webService搞定,下面给大家分享一下发布webService和调用webService的方法

1. 添加jar包 (官方下载地址:http://cxf.apache.org/download.html 为了方便扩展我把所有的jar包都加了)
2. 在web.xml中配置spirng以及CXF

   <?xml version="1.0" encoding="UTF-8"?>
   
   <web-app version="2.5"
   
       xmlns="http://java.sun.com/xml/ns/javaee"
   
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   
       xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
   
       http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
   
     <display-name></display-name>
   
     <welcome-file-list>
   
       <welcome-file>index.jsp</welcome-file>
   
     </welcome-file-list>
   
     <!-- spring -->
   
     <context-param>
   
         <param-name>contextConfigLocation</param-name>
   
         <param-value>classpath:applicationContext.xml</param-value>
   
     </context-param>
   
     <listener>
   
       <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
   
     </listener>
   
     <listener>
   
         <listener-class>org.springframework.web.util.IntrospectorCleanupListener</listener-class>
   
     </listener>
   
       <!-- CXFService -->
   
       <servlet>
   
           <servlet-name>CXFService</servlet-name>
   
           <servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
   
       </servlet>
   
       <servlet-mapping>
   
           <servlet-name>CXFService</servlet-name>
   
           <url-pattern>/*</url-pattern>
   
       </servlet-mapping>
   
   </web-app>

   3.写接口实现类   要发布webService的类及要被调用的接口

   package cn.com.lrl.service.impl;
   
   import javax.jws.WebParam;
   
   import javax.jws.WebResult;
   
   import javax.jws.WebService;
   
   import cn.com.lrl.service.JAXService;
   
   @WebService
   
   public class JAXServiceImpl implements JAXService {
   
       @Override
   
       public @WebResult(name="news")String sayHello(@WebParam(name="name") String name) {
   
           return name +"   hello!";
   
       }

   4.配置spirng配置文件,发布webService  jaxws:server 标签中的address 中的路径 就是访问webService的路径  实际路径是http://localhost:8080/ws/Users?wsdl(ws是项目名)

   <?xml version="1.0" encoding="UTF-8"?>
   
   <beans xmlns="http://www.springframework.org/schema/beans"
   
           xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   
            xmlns:jaxws="http://cxf.apache.org/jaxws"
   
           xsi:schemaLocation="
   
               http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
   
               http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd"
   
               >
   
           <!-- 发布的webService类 -->
   
           <bean id="userServiceBean" class="cn.com.lrl.service.impl.JAXServiceImpl"/>
   
           <!-- 注意下面的address，这里的address的名称就是访问的WebService的name -->
   
           <jaxws:server id="userService" serviceClass="cn.com.lrl.service.JAXService" address="/Users">
   
               <jaxws:serviceBean>
   
                   <!-- 要暴露的 bean 的引用 -->
   
                   <ref bean="userServiceBean"/>
   
               </jaxws:serviceBean>
   
               <!-- 添加请求日志 -->
   
               <jaxws:inInterceptors>
   
                   <bean class="org.apache.cxf.interceptor.LoggingInInterceptor"/>
   
               </jaxws:inInterceptors>
   
                  <!-- 添加响应 日志 -->
   
               <jaxws:outInterceptors>
   
                   <bean class="org.apache.cxf.interceptor.LoggingOutInterceptor"/>
   
                  </jaxws:outInterceptors>
   
           </jaxws:server>
   
   </beans>

   5.启动tomcat发布webService 访问你的webService  如果是这样就代表成功了6.通过wsimport解析wsdl文件

　　7.将生成的代码复制到要调用webService的项目

　　8.测试接口是否可以使用

public class Test {

    public static void main(String[] args) {

        JAXServiceService jaxServiceService =new JAXServiceService();

        JAXService jaxService=jaxServiceService.getJAXServicePort();

        //调用方法输出

        System.out.println(jaxService.sayHello("lrl"));

    }

}

　　9.调用成功 控制台输出