当我将数据提取到ListView中时,以相同的顺序获取数据,但是如果我想基于MemberID对数据进行排序,但是我想在顶部显示最新的数据

public class AppointmentsActivity extends Activity {

    ...
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        ....
        adapter = new MembersAdapter (MembersActivity.this, R.layout.adapter_members, membersArrayList);

        listView.setAdapter(adapter);

    }

    ........
}

解决方法:

如果您使用Java 8开发,则可以使用lambda表达式：

Collections.sort(membersArrayList, 
     (m1, m2) -> (int) (m2.getMemberID() - m1.getMemberID()));