新版本对直方图不再使用之前的histogram的形式，而是用统一的Mat或者MatND的格式来存储直方图，可见新版本Mat数据结构的优势。

C++: void calcHist(const Mat* images, int nimages, const int* channels, InputArray mask, OutputArray hist, intdims, const int* histSize, const float** ranges, bool uniform=true, bool accumulate=false )

计算直方图

Parameters:

• images – Source arrays. They all should have the same depth, CV_8U or CV_32F , and the same size. Each of them can have an arbitrary number of channels.
• nimages – Number of source images.
• channels – List of the dims channels used to compute the histogram. The first array channels are numerated from 0 to images[0].channels()-1 , the second array channels are counted fromimages[0].channels() to images[0].channels() + images[1].channels()-1, and so on.
• mask – Optional mask. If the matrix is not empty, it must be an 8-bit array of the same size asimages[i] . The non-zero mask elements mark the array elements counted in the histogram.
• hist – Output histogram, which is a dense or sparse dims -dimensional array.
• dims – Histogram dimensionality that must be positive and not greater than CV_MAX_DIMS (equal to 32 in the current OpenCV version).
• histSize – Array of histogram sizes in each dimension.
• ranges – Array of the dims arrays of the histogram bin boundaries in each dimension. When the histogram is uniform ( uniform =true), then for each dimension i it is enough to specify the lower (inclusive) boundary of the 0-th histogram bin and the upper (exclusive) boundary for the last histogram bin histSize[i]-1 . That is, in case of a uniform histogram each ofranges[i] is an array of 2 elements. When the histogram is not uniform ( uniform=false ), then each of ranges[i] contains histSize[i]+1 elements: . The array elements, that are not between and , are not counted in the histogram.
• uniform – Flag indicating whether the histogram is uniform or not (see above).
• accumulate – Accumulation flag. If it is set, the histogram is not cleared in the beginning when it is allocated. This feature enables you to compute a single histogram from several sets of arrays, or to update the histogram in time.

void rectangle(Mat& img, Point pt1, Point pt2, const Scalar& color, int thickness=1, int lineType=8, intshift=0)

画矩形

#include "stdafx.h"

#include <cv.h>

#include <highgui.h>

using namespace cv;

int main( int argc, char** argv )

{

    Mat src, hsv;

    /* if( argc != 2 || !(src=imread(argv[1], 1)).data )

        return -1; */

    src=imread("zhang.jpg", 1);

    cvtColor(src, hsv, CV_BGR2HSV);

    // Quantize the hue to 30 levels

    // and the saturation to 32 levels

    int hbins = 30, sbins = 32;        // bin 步长

    int histSize[] = {hbins, sbins};

    // hue varies from 0 to 179, see cvtColor

    float hranges[] = { 0, 180 };

    // saturation varies from 0 (black-gray-white) to

    // 255 (pure spectrum color)

    float sranges[] = { 0, 256 };

    const float* ranges[] = { hranges, sranges };

    MatND hist;

    // we compute the histogram from the 0-th and 1-st channels

    int channels[] = {0, 1};   // --- hue && saturation

    calcHist( &hsv, 1, channels, Mat(), // do not use mask

        hist, 2, histSize, ranges,

        true, // the histogram is uniform

        false );

    double maxVal=0;

    minMaxLoc(hist, 0, &maxVal, 0, 0);  // Finds the global minimum and maximum in an array.

        // void minMaxLoc(InputArray src, double* minVal, double* maxVal=0, Point* minLoc=0, Point* maxLoc=0, InputArray mask=noArray())

    // 直方图显示

    int scale = 10;

    Mat histImg = Mat::zeros(sbins*scale, hbins*10, CV_8UC3);

    for( int h = 0; h < hbins; h++ )

        for( int s = 0; s < sbins; s++ )

        {

            float binVal = hist.at<float>(h, s);

            int intensity = cvRound(binVal*255/maxVal);

            rectangle( histImg, Point(h*scale, s*scale),

                Point( (h+1)*scale - 1, (s+1)*scale - 1),

                Scalar::all(intensity),    // 二维直方图，颜色之深浅代表出现个数之多寡

                CV_FILLED );

        }

        namedWindow( "Source", 1 );

        imshow( "Source", src );

        namedWindow( "H-S Histogram", 1 );

        imshow( "H-S Histogram", histImg );

        waitKey();

}

C++: void equalizeHist(InputArray src, OutputArray dst)

直方图均衡化

Parameters:

• src – Source 8-bit single channel image.
• dst – Destination image of the same size and type as src .

The function equalizes the histogram of the input image using the following algorithm:

1. Calculate the histogram for src .

2. Normalize the histogram so that the sum of histogram bins is 255.

3. Compute the integral of the histogram:

   

4. Transform the image using as a look-up table:

5. 

compareHist

double compareHist(const SparseMat& H1, const SparseMat& H2, int method)

直方图比较

Parameters:

• H1 – First compared histogram.
• H2 – Second compared histogram of the same size as H1 .
• method –

  Comparison method that could be one of the following:

  • CV_COMP_CORREL Correlation  相关性 相同为1，范围0<x<=1
  • CV_COMP_CHISQR Chi-Square   卡方 相同为0 [0,inf)
  • CV_COMP_INTERSECT Intersection   直方图交 ，数值越大越相似
  • CV_COMP_BHATTACHARYYA Bhattacharyya distance
  • CV_COMP_HELLINGER Synonym for CV_COMP_BHATTACHARYYA Bhattacharyya 距离，相同为0 [0,inf)

#include "stdafx.h"

#include <cv.h>

#include <highgui.h>

#include "stdio.h"

using namespace std;

using namespace cv;

int main( int argc, char** argv )

{

    Mat src1, src2,dst;

    Mat hsv1,hsv2;

    MatND hist1,hist2;

    src1=imread("zhang.jpg", 1);

    src2=imread("zhou.jpg",1);

    cvtColor(src1,hsv1,CV_RGB2HSV);

    cvtColor(src2,hsv2,CV_RGB2HSV);

    int hbins=30,sbins=32;

    int histSize[]={hbins,sbins};

    float hranges[]={0,180};

    float sranges[]={0,256};

    const float* ranges[]={hranges,sranges};

    int channels[]={0,1};

    calcHist(&hsv1,1,channels,Mat(),hist1,2,histSize,ranges,true,false);

    calcHist(&hsv2,1,channels,Mat(),hist2,2,histSize,ranges,true,false);

    double temp;

    temp=compareHist(hist1,hist2,CV_COMP_CORREL);

    cout<<"CV_COMP_CORREL  "<<temp<<endl;

    temp=compareHist(hist1,hist2,CV_COMP_CHISQR);

    cout<<"CV_COMP_CHISQR  "<<temp<<endl;

    temp=compareHist(hist1,hist2,CV_COMP_INTERSECT);

    cout<<"CV_COMP_INTERSECT  "<<temp<<endl;

    temp=compareHist(hist1,hist2,CV_COMP_BHATTACHARYYA);

    cout<<"CV_COMP_BHATTACHARYYA  "<<temp<<endl;

    namedWindow("src1");

    imshow("src1",src1);

    namedWindow("src2");

    imshow("src2",src2);

    waitKey();

    cvDestroyAllWindows();

    return 0;

}

遇到 ~ 编译器错误 C2078

初始值设定项的数目超过了要初始化的对象数。

// C2078.cpp

int main() {

   int d[2] = {1, 2, 3};   // C2078

   int e[2] = {1, 2};   // OK

   char a[]={"a", "b"};   // C2078

   char *b[]={"a", "b"};   // OK

   char c[]={'a', 'b'};   // OK

}