我目前正在制作一个农业游戏,您在其中使用盆栽植物.我拥有的每个盆栽都应可单击,并应提供在其中种下种子的选项.到目前为止,我想出了一种非最佳方式来实现这一目标.我想知道是否可以使用循环以更少的代码行整齐地循环每个语句.
这是我当前的代码如下所示:
if (HUD.pots == 1) {
// First pot 230, 502, 40, 50. Every new pot adds 50 to X
if (mouseOver(mx, my, 230, 502, 40, 50)) {
AudioPlayer.getSound("menu_sound").play();
Game.gameState = STATE.Game;
return;
}
} else if(HUD.pots == 2) {
if (mouseOver(mx, my, 230, 502, 40, 50)) {
AudioPlayer.getSound("menu_sound").play();
Game.gameState = STATE.Game;
return;
} else if (mouseOver(mx, my, 280, 502, 40, 50)) {
AudioPlayer.getSound("menu_sound").play();
Game.gameState = STATE.Game;
return;
}
} else if (HUD.pots == 3) {
if (mouseOver(mx, my, 230, 502, 40, 50)) {
AudioPlayer.getSound("menu_sound").play();
Game.gameState = STATE.Game;
return;
} else if (mouseOver(mx, my, 280, 502, 40, 50)) {
AudioPlayer.getSound("menu_sound").play();
Game.gameState = STATE.Game;
return;
} else if (mouseOver(mx, my, 330, 502, 40, 50)) {
AudioPlayer.getSound("menu_sound").play();
Game.gameState = STATE.Game;
return;
}
}
当我最终要为游戏添加更多的底池时,我将需要很多行来遍历所有底池.
对于另一种情况,我也有类似的问题:每次购买新锅时,如何使它产卵x 50?
码:
// Buy Pot
if (mouseOver(mx, my, 220, 140, 40, 20)) {
AudioPlayer.getSound("menu_sound").play();
if (HUD.money >= UpgradePrices.potPrice) {
HUD.money -= UpgradePrices.potPrice;
HUD.pots += 1;
if (HUD.pots == 1) {
handler.addObject(new Pot((int)230, (int)502, ID.Pot, handler));
} else if (HUD.pots == 2) {
handler.addObject(new Pot((int)280, (int)502, ID.Pot, handler));
} else if (HUD.pots == 3) {
handler.addObject(new Pot((int)330, (int)502, ID.Pot, handler));
}
Game.gameState = STATE.Upgrades;
return;
解决方法:
对于购买锅,您可以应用相同的想法:
if (mouseOver(mx, my, 220, 140, 40, 20)){ //Assume this position is fixed
AudioPlayer.getSound("menu_sound").play();
if (HUD.money >= UpgradePrices.potPrice){
HUD.money -= UpgradePrices.potPrice;
HUD.pots += 1;
}
for(int x=0; x<HUD.pots; x++){ //Once again, this will replace all the ifs
handler.addObject(new Pot(( 230+(x*50), 502, ID.Pot, handler )))
}
}