我以为我已经学到足够多的Python来制作凯撒密码了,所以我开始制作它,而我碰到了砖墙.

这是我的代码：

phrase = raw_input("Enter text to Cipher: ")
shift = int(raw_input("Please enter shift: "))
result = ("Encrypted text is: ")

for character in phrase:
    x = ord(character)

    x = x + shift


print chr(x)

目前,如果短语为“ hi”且shift为1,则for循环仅围绕字母i而不是字母h循环,因此我的结果是：j

我想遍历整个单词,并通过shift int变量来移动每个字母.

如何在短语变量周围循环？

解决方法:

您的代码正在打印ord()值“ j”,因为循环末尾的字符等于“ i”.您应该将新字符存储到列表中,并在循环结束后将它们加入并进行打印.

new_strs = []
for character in phrase:
    x = ord(character)
    x = x + shift
    new_strs.append(chr(x))   #store the new shifted character to the list
    #use this if you want z to shift to 'a'
    #new_strs.append(chr(x if 97 <= x <= 122 else 96 + x % 122))
print "".join(new_strs)       #print the new string

演示：

$python so.py
Enter text to Cipher: hi
Please enter shift: 1
ij