Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.
Input Specification:
Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).
Output Specification:
For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.
Sample Input:
12345
Sample Output:
one five 很简单的题，最开始错了两次，N最大是10得100次方，用整形存储肯定不够，用字符串存储后就过了
#include <iostream>
#include <string>
#include <map> using namespace std; map<char,string> m;
int result[]; int main()
{
m[]="zero";
m[]="one";
m[]="two";
m[]="three";
m[]="four";
m[]="five";
m[]="six";
m[]="seven";
m[]="eight";
m[]="nine";
string n;
long int sum=;
cin>>n;
int b,i=;
while(n[i]!='\0'){
b=n[i]-;
sum=sum+b;
i++;
}
int x,countnum=;
while(sum){
x=sum%;
result[countnum]=x;
countnum++;
sum=sum/;
}
cout<<m[result[countnum-]];
for(int i=countnum-;i>=;i--){
cout<<" "<<m[result[i]];
} return ;
}