令人困惑的Java语法

我正在尝试将以下代码(从Wikipedia)从Java转换为JavaScript:

/*
 * 3 June 2003, [[:en:User:Cyp]]:
 *     Maze, generated by my algorithm
 * 24 October 2006, [[:en:User:quin]]:
 *     Source edited for clarity
 * 25 January 2009, [[:en:User:DebateG]]:
 *     Source edited again for clarity and reusability
 * 1 June 2009, [[:en:User:Nandhp]]:
 *     Source edited to produce SVG file when run from the command-line
 *
 * This program was originally written by [[:en:User:Cyp]], who
 * attached it to the image description page for an image generated by
 * it on en.wikipedia. The image was licensed under CC-BY-SA-3.0/GFDL.
 */

import java.awt.*;
import java.applet.*;
import java.util.Random;

/* Define the bit masks */
class Constants {
    public static final int WALL_ABOVE = 1;
    public static final int WALL_BELOW = 2;
    public static final int WALL_LEFT = 4;
    public static final int WALL_RIGHT = 8;
    public static final int QUEUED = 16;
    public static final int IN_MAZE = 32;
}

public class Maze extends java.applet.Applet {
    /* The width and height (in cells) of the maze */
    private int width;
    private int height;
    private int maze[][];
    private static final Random rnd = new Random();

    /* The width in pixels of each cell */
    private int cell_width;

    /* Construct a Maze with the default width, height, and cell_width */
    public Maze() {
 this(20,20,10);
    }

    /* Construct a Maze with specified width, height, and cell_width */
    public Maze(int width, int height, int cell_width) {
 this.width = width;
 this.height = height;
 this.cell_width = cell_width;
    }

    /* Initialization method that will be called when the program is
     * run from the command-line. Maze will be written as SVG file. */
    public static void main(String[] args) {
 Maze m = new Maze();
 m.createMaze();
 m.printSVG();
    }

    /* Initialization method that will be called when the program is
     * run as an applet. Maze will be displayed on-screen. */
    public void init() {
 createMaze();
    }

    /* The maze generation algorithm. */
    private void createMaze(){
 int x, y, n, d;
 int dx[] = { 0, 0, -1, 1 };
 int dy[] = { -1, 1, 0, 0 };

 int todo[] = new int[height * width], todonum = 0;

 /* We want to create a maze on a grid. */
 maze = new int[width][height];

 /* We start with a grid full of walls. */
 for (x = 0; x < width; ++x) {
     for (y = 0; y < height; ++y) {
  if (x == 0 || x == width - 1 || y == 0 || y == height - 1) {
      maze[x][y] = Constants.IN_MAZE;
  } else {
      maze[x][y] = 63;
  }
     }
 }

 /* Select any square of the grid, to start with. */
 x = 1 + rnd.nextInt (width - 2);
 y = 1 + rnd.nextInt (height - 2);

 /* Mark this square as connected to the maze. */
 maze[x][y] &= ~48;

 /* Remember the surrounding squares, as we will */
 for (d = 0; d < 4; ++d) {
     if ((maze[][d][][d] & Constants.QUEUED) != 0) {
  /* want to connect them to the maze. */              
  todo[todonum++] = ((x + dx[d]) << Constants.QUEUED) | (y + dy[d]);
  maze[][d][][d] &= ~Constants.QUEUED;
     }
 }

 /* We won't be finished until all is connected. */
 while (todonum > 0) {
     /* We select one of the squares next to the maze. */
     n = rnd.nextInt (todonum);
     x = todo[n] >> 16; /* the top 2 bytes of the data */
     y = todo[n] & 65535; /* the bottom 2 bytes of the data */

     /* We will connect it, so remove it from the queue. */
     todo[n] = todo[--todonum];

     /* Select a direction, which leads to the maze. */
     do {
  d = rnd.nextInt (4);
     }
     while ((maze[][d][][d] & Constants.IN_MAZE) != 0);

     /* Connect this square to the maze. */
     maze[x][y] &= ~((1 << d) | Constants.IN_MAZE);
     maze[][d][][d] &= ~(1 << (d ^ 1));

     /* Remember the surrounding squares, which aren't */
     for (d = 0; d < 4; ++d) {
  if ((maze[][d][][d] & Constants.QUEUED) != 0) {      
      /* connected to the maze, and aren't yet queued to be. */
      todo[todonum++] = ((x + dx[d]) << Constants.QUEUED) | (y + dy[d]);
      maze[][d][][d] &= ~Constants.QUEUED;
  }
     }
            /* Repeat until finished. */
        }

        /* Add an entrance and exit. */
        maze[1][1] &= ~Constants.WALL_ABOVE; 
        maze[width - 2][height - 2] &= ~Constants.WALL_BELOW;
    }

    /* Called by the applet infrastructure to display the maze on-screen. */
    public void paint(Graphics g) {
 drawMaze(g);
    }

    /* Called to write the maze to an SVG file. */
    public void printSVG() {
 System.out.format("<svg width=\"%d\" height=\"%d\" version=\"1.1\""
     + " xmlns=\"http://www.w3.org/2000/svg\">\n",
     width*cell_width, height*cell_width);
 System.out.println("  <g stroke=\"black\" stroke-width=\"1\""
      + " stroke-linecap=\"round\">");
 drawMaze(null);
 System.out.println("  </g>\n</svg>");
    }

    /* Main maze-drawing loop. */
    public void drawMaze(Graphics g) {
        int x, y;

        for (x = 1; x < width - 1; ++x) {
            for (y = 1; y < height - 1; ++y) {
                if ((maze[x][y] & Constants.WALL_ABOVE) != 0)
      drawLine(      x * cell_width,       y * cell_width,
        (x + 1) * cell_width,       y * cell_width, g);
                if ((maze[x][y] & Constants.WALL_BELOW) != 0)
      drawLine(      x * cell_width, (y + 1) * cell_width,
        (x + 1) * cell_width, (y + 1) * cell_width, g);
                if ((maze[x][y] & Constants.WALL_LEFT) != 0)
      drawLine(      x * cell_width,       y * cell_width,
              x * cell_width, (y + 1) * cell_width, g);
                if ((maze[x][y] & Constants.WALL_RIGHT) != 0)
      drawLine((x + 1) * cell_width,       y * cell_width,
        (x + 1) * cell_width, (y + 1) * cell_width, g);
     }
 }
    }

    /* Draw a line, either in the SVG file or on the screen. */
    public void drawLine(int x1, int y1, int x2, int y2, Graphics g) {
 if ( g != null ) g.drawLine(x1, y1, x2, y2);
 else System.out.format("    <line x1=\"%d\" y1=\"%d\""
          + " x2=\"%d\" y2=\"%d\" />\n", x1, y1, x2, y2);
    }
}

无论如何,当我谈到一些我不明白的时候,我相当快地匆匆忙忙:

 /* Remember the surrounding squares, as we will */
 for (var d = 0; d < 4; ++d) {
     if ((maze[][d][][d] & Constants.QUEUED) != 0) {
  /* want to connect them to the maze. */              
  todo[todonum++] = ((x + dx[d]) << Constants.QUEUED) | (y + dy[d]);
  maze[][d][][d] &= ~Constants.QUEUED;
     }
 }

我没有得到的是为什么“迷宫”参数后面有四组括号而不是两个,因为“迷宫”是二维数组,而不是四维数组.

我确信这是有充分理由的.问题是,我只是不明白.

谢谢!

最佳答案:

要简单地纠正语法,这个答案就像任何答案一样好.然而,要修复算法,Leon在那里有更多的洞察力.

在我看来,代码是错误的,有两组方括号.迷宫被声明并初始化为2维int数组.没有理由它应该有更多.可能是错误信息或错误代码生成器的结果?

只需从数组访问中删除前面的空方括号[](或] [],即可进行设置.

上一篇:用Q-learning算法实现自动走迷宫机器人


下一篇:为物联网代码安全而生 网易易盾公测IoT安全编译器Maze