#*args（元组列表）和**kwargs（字典）的区别

def tuple_test(*args):

    for i in args:

        print 'hello'+i

s=('xuexi','mili')

tuple_test(*s)

结果

helloxuexi
hellomili

def dict_test(**kwargs):

    for i in kwargs:

        print i,kwargs[i]

ss={'name':'xuexi',"nick":''}

dict_test(**ss)

结果：

nick 0000
name xuexi

3,可变参数和关键字参数

def func(*args, **kwargs):

    return sum(args) + sum(kwargs.values())

args = [1, 2]

kwargs = {'a':3, 'b':4}

func(*args, **kwargs)

# => 3+7  10

args = []

kwargs = {'a':3, 'b':4, 'c': 5}

func(*args, **kwargs)

 # =>0+12  12

https://blog.csdn.net/parameter_/article/details/78555470

def foo(*args,**kwargs):
print 'args is',args
print 'kwargs is',kwargs
foo(1,2)
foo(k=1,w=2,a=3,r=4,g=5,s=6)
foo(1,2,a=1,b=2,c=2)
foo('a',1,None,a=1,b='2',c=3)

结果

args is (1, 2)
kwargs is {}
args is ()
kwargs is {'a': 3, 'g': 5, 'k': 1, 's': 6, 'r': 4, 'w': 2}
args is (1, 2)
kwargs is {'a': 1, 'c': 2, 'b': 2}
args is ('a', 1, None)
kwargs is {'a': 1, 'c': 3, 'b': '2'}