Given a sorted integer array without duplicates, return the summary of its ranges.
For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"].
题目大意：给一个有序数组，返回连续的区间范围。
public class Solution {
public List<String> summaryRanges(int[] nums) {
List<String> res = new ArrayList<>();
if(nums==null||nums.length==0){
return res;
}
for(int i=0;i<nums.length;i++){
int t = nums[i];
while(i<nums.length-1&&nums[i]+1==nums[i+1]){
i++;
}
String se = "" + t;
if(t!=nums[i])
se = t+"->"+nums[i];
res.add(se);
}
return res;
}
}