翻转单词顺序 代码(C)

本文地址: http://blog.csdn.net/caroline_wendy

题目: 输入一个英文句子, 翻转句子中单词的顺序, 但单词内字符的顺序不变.

首先翻转(reverse)整个句子, 然后查找空格, 如遇到空格, 则翻转前面的单词, 或遇到结束符, 相同进行翻转.

代码:

/*

 * main.cpp

 *

 *  Created on: 2014.9.19

 *      Author: spike

 */

#include <iostream>

#include <vector>

#include <climits>

#include <cstring>

using namespace std;

void Reverse(char* begin, char* end) {

	if (begin == NULL || end == NULL)

		return;

	while(begin < end) {

		char tmp = *begin;

		*begin++ = *end;

		*end-- = tmp;

	}

}

char* ReverseWords(char* data) {

	if (data == NULL) return NULL;

	int len = strlen(data);

	char* begin = data;

	char* end = &data[len-1];

	Reverse(begin, end);

	begin = end = data;

	while(*begin != '\0') {

		if (*begin == ' ') {

			begin++;

			end++;

		} else if (*end == ' ' || *end == '\0') {

			Reverse(begin, --end);

			begin = ++end;

		} else {

			++end;

		}

	}

	return data;

}

int main(void)

{

	char data[] = "I am Spike.";

	char* res = ReverseWords(data);

	cout << res << endl;

    return 0;

}

输出:

Spike. am I