Python 冒泡法排序

一. Python 冒泡法排序
def sequence(arrays=list()): def desc():
for i in range(1, len(arrays)):
for j in range(len(arrays) - i):
if arrays[j] < arrays[j + 1]:
arrays[j], arrays[j + 1] = arrays[j + 1], arrays[j]
return arrays def asc():
for i in range(1, len(arrays)):
for j in range(len(arrays) - i):
if arrays[j] > arrays[j + 1]:
arrays[j], arrays[j + 1] = arrays[j + 1], arrays[j]
return arrays print desc()
print asc() if __name__ == "__main__": sequence([1, 2, -1, 10, 12, 9, 13, 14]) 二. 有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少?
def combinations():

    num = [1, 2, 3, 4]
   # 列表解析
res = [i * 100 + j * 10 + k for i in num for j in num for k in num if(j != i and k != j and k != i)] print (res) if __name__ == "__main__": combinations() 三、输出100以内的质数(大于1的且因数只有它自身与1的自然数)
def prime_num():

    count = 0

    for i in range(2, 100):

        for j in range(2, i):
if i % j == 0:
break
else:
print i,
count += 1 print
print "total: " + str(count) if __name__ == "__main__": prime_num()
四、打印九九乘法表

def multiplication_tables():

    for i in range(1, 10):
print for j in range(1, i + 1):
print "%d*%d=%d" % (i, j, i * j), if __name__ == "__main__": multiplication_tables()
五、斐波那契数列
def recur_fibo(n):
   """递归函数
   输出斐波那契数列"""
   if n <= 1:
       return n
   else:
       return(recur_fibo(n-1) + recur_fibo(n-2))
 
# 获取用户输入
nterms = int(input("您要输出几项? "))
 
# 检查输入的数字是否正确
if nterms <= 0:
   print("输入正数")
else:
   print("斐波那契数列:")
   for i in range(nterms):
       print(recur_fibo(i))
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