/*

     模拟：手敲map一一映射，累！

         除了忘记读入字符串不能用gets用getline外还是很顺利的AC了:)

 */

 #include <cstdio>

 #include <iostream>

 #include <algorithm>

 #include <cmath>

 #include <cstring>

 #include <string>

 #include <map>

 #include <set>

 #include <queue>

 #include <vector>

 using namespace std;

 const int MAXN = 1e2 + ;

 const int INF = 0x3f3f3f3f;

 map<char, char> m;

 string s;

 void solve(void)

 {

     m['~'] = '~';   m['`'] = '`';

     m['!'] = '!';   m[''] = '';

     m['@'] = '@';   m[''] = '';

     m['#'] = '#';   m[''] = '';

     m['$'] = '$';   m[''] = '';

     m['%'] = '%';   m[''] = '';

     m['^'] = '^';   m[''] = '';

     m['&'] = '&';   m[''] = '';

     m['*'] = '*';   m[''] = '';

     m['('] = '(';   m[''] = '';

     m[')'] = ')';   m[''] = '';

     m['_'] = '{';   m['-'] = '[';

     m['+'] = '}';   m['='] = ']';

     m['Q'] = '"';   m['q'] = '\'';

     m['W'] = '<';   m['w'] = ',';

     m['E'] = '>';   m['e'] = '.';

     m['R'] = 'P';   m['r'] = 'p';

     m['T'] = 'Y';   m['t'] = 'y';

     m['Y'] = 'F';   m['y'] = 'f';

     m['U'] = 'G';   m['u'] = 'g';

     m['I'] = 'C';   m['i'] = 'c';

     m['O'] = 'R';   m['o'] = 'r';

     m['P'] = 'L';   m['p'] = 'l';

     m['{'] = '?';   m['['] = '/';

     m['}'] = '+';   m[']'] = '=';

     m['|'] = '|';   m['\\'] = '\\';

     m['A'] = 'A';   m['a'] = 'a';

     m['S'] = 'O';   m['s'] = 'o';

     m['D'] = 'E';   m['d'] = 'e';

     m['F'] = 'U';   m['f'] = 'u';

     m['G'] = 'I';   m['g'] = 'i';

     m['H'] = 'D';   m['h'] = 'd';

     m['J'] = 'H';   m['j'] = 'h';

     m['K'] = 'T';   m['k'] = 't';

     m['L'] = 'N';   m['l'] = 'n';

     m[':'] = 'S';   m[';'] = 's';

     m['"'] = '_';   m['\''] = '-';

     m['Z'] = ':';   m['z'] = ';';

     m['X'] = 'Q';   m['x'] = 'q';

     m['C'] = 'J';   m['c'] = 'j';

     m['V'] = 'K';   m['v'] = 'k';

     m['B'] = 'X';   m['b'] = 'x';

     m['N'] = 'B';   m['n'] = 'b';

     m['M'] = 'M';   m['m'] = 'm';

     m['<'] = 'W';   m[','] = 'w';

     m['>'] = 'V';   m['.'] = 'v';

     m['?'] = 'Z';   m['/'] = 'z';

     m[' '] = ' ';

 }

 int main(void)      //ZOJ 3878 Convert QWERTY to Dvorak

 {

     //freopen ("J.in", "r", stdin);

     solve ();

     while (getline (cin, s))

     {

         for (int i=; s[i]; ++i)

             cout << m[s[i]];

         cout << endl;

     }

     return ;

 }

 /*

 Hi, I'm Abel, a Dvorak Layout user.

 But I've only a Qwerty keyboard.

 The following lines are for testing:

 1234567890

 `~!@#$%^&*()+_-={}[]:"'<>,.?/\|

 ABCDEFuvwxyz

 AXJE>Ugk,qf;

 */

 #include <iostream>

 #include <stdio.h>

 #include <string.h>

 #include <stack>

 #include <queue>

 #include <map>

 #include <set>

 #include <vector>

 #include <math.h>

 #include <algorithm>

 using namespace std;

 #define ls 2*i

 #define rs 2*i+1

 #define up(i,x,y) for(i=x;i<=y;i++)

 #define down(i,x,y) for(i=x;i>=y;i--)

 #define mem(a,x) memset(a,x,sizeof(a))

 #define w(a) while(a)

 #define LL long long

 const double pi = acos(-1.0);

 #define Len 20005

 #define mod 19999997

 const int INF = 0x3f3f3f3f;

 char s1[]= {"-=_+qwertyuiop[]QWERTYUIOP{}asdfghjkl;'ASDFGHJKL:\"zxcvbnm,./ZXCVBNM<>?"};

 char s2[]= {"[]{}',.pyfgcrl/=\"<>PYFGCRL?+aoeuidhtns-AOEUIDHTNS_;qjkxbmwvz:QJKXBMWVZ"};

 char c;

 char print(char c)

 {

     for(int i=; s1[i]; i++)

         if(s1[i]==c)

             return s2[i];

     return c;

 }

 int main()

 {

     w(~scanf("%c",&c))

     printf("%c",print(c));

     return ;

 }

网上题解，两行，给跪了！