Given a sorted (in ascending order) integer array nums
of n
elements and a target
value, write a function to search target
in nums
. If target
exists, then return its index, otherwise return -1
.
Example 1:
Input:nums
= [-1,0,3,5,9,12],target
= 9
Output: 4
Explanation: 9 exists innums
and its index is 4
Example 2:
Input:nums
= [-1,0,3,5,9,12],target
= 2
Output: -1
Explanation: 2 does not exist innums
so return -1
Note:
- You may assume that all elements in
nums
are unique. -
n
will be in the range[1, 10000]
. - The value of each element in
nums
will be in the range[-9999, 9999]
.
Approach #1:
class Solution {
public:
int search(vector<int>& nums, int target) {
int len = nums.size();
int l = 0, r = len-1;
while (l <= r) {
int m = l + (r - l) / 2;
if (nums[m] == target) return m;
else if (nums[m] > target) r = m - 1;
else l = m + 1;
}
return -1;
}
};
Runtime: 52 ms, faster than 31.47% of C++ online submissions for Binary Search.