704. Binary Search

Given a sorted (in ascending order) integer array nums of n elements and a target value, write a function to search target in nums. If targetexists, then return its index, otherwise return -1.

Example 1:

Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4
Explanation: 9 exists in nums and its index is 4

Example 2:

Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1
Explanation: 2 does not exist in nums so return -1

Note:

  1. You may assume that all elements in nums are unique.
  2. n will be in the range [1, 10000].
  3. The value of each element in nums will be in the range [-9999, 9999].
 
Approach #1:
class Solution {
public:
int search(vector<int>& nums, int target) {
int len = nums.size();
int l = 0, r = len-1;
while (l <= r) {
int m = l + (r - l) / 2;
if (nums[m] == target) return m;
else if (nums[m] > target) r = m - 1;
else l = m + 1;
}
return -1;
}
};

Runtime: 52 ms, faster than 31.47% of C++ online submissions for Binary Search.

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