Problem 5

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.

What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?

Solve：

1. clear
   clc
   for i = 100:20:1000000000
   % if rem(i,11) == 0 && rem(i,12) == 0 && rem(i,13) == 0 && rem(i,14) == 0 && rem(i,15) == 0 &&rem(i,16) == 0 && rem(i,17) == 0 && rem(i,18) == 0 && rem(i,19) == 0 && rem(i,20) == 0
   break
   end
   end
   fprintf('The smallest evenly divisible number is %.0d\n',i)

2. clear
   clc
   for i = 100:20:1000000000
   for j = 20:-1:1
   if mod(i,j) ~= 0
   break
   end
   end
   if j == 1
   answer = i;
   break
   end
   end
   fprintf('The smallest evenly divisible number is %.0d\n',answer)