面向对象程序设计上机练习一（函数重载）

Time Limit: 1000 ms Memory Limit: 65536 KiB

Problem Description

利用数组和函数重载求5个数最大值（分别考虑整数、单精度、长整数的情况）。

Input

分别输入5个int型整数、5个float 型实数、5个long型正整数。

Output

分别输出5个int型整数的最大值、5个float 型实数的最大值、5个long型正整数的最大值。

Sample Input

11 22 666 44 55

11.11 22.22 33.33 888.88 55.55

1234567 222222 333333 444444 555555

Sample Output

666

888.88

1234567

Hint

Source

zlh

import java.util.*;

public class Main

{

	public static void main(String[] args)

	{

		Scanner cin = new Scanner(System.in);

		int a1,b1,c1,d1,e1,m1;

		float a2,b2,c2,d2,e2,m2;

		long a3,b3,c3,d3,e3,m3;

		a1 = cin.nextInt();

		b1 = cin.nextInt();

		c1 = cin.nextInt();

		d1 = cin.nextInt();

		e1 = cin.nextInt();

		m1 = max(a1,b1,c1,d1,e1);

		a2 = cin.nextFloat();

		b2 = cin.nextFloat();

		c2 = cin.nextFloat();

		d2 = cin.nextFloat();

		e2 = cin.nextFloat();

		m2 = max(a2,b2,c2,d2,e2);

		a3 = cin.nextLong();

		b3 = cin.nextLong();

		c3 = cin.nextLong();

		d3 = cin.nextLong();

		e3 = cin.nextLong();

		m3 = max(a3,b3,c3,d3,e3);

		System.out.println(m1+"\n"+m2+"\n"+m3);

		cin.close();

	}

	static int max(int a,int b,int c,int d,int e)

	{

		int m;

		m  = a;

		if(m<b)

			m = b;

		if(m<c)

			m = c;

		if(m<d)

			m = d;

		if(m<e)

			m = e;

		return m;

	}

	static float max(float a,float b,float c,float d,float e)

	{

		float m;

		m  = a;

		if(m<b)

			m = b;

		if(m<c)

			m = c;

		if(m<d)

			m = d;

		if(m<e)

			m = e;

		return m;

	}

	static long max(long a,long b,long c,long d,long e)

	{

		long m;

		m  = a;

		if(m<b)

			m = b;

		if(m<c)

			m = c;

		if(m<d)

			m = d;

		if(m<e)

			m = e;

		return m;

	}

}