题意：
输入一个正整数N（<100），接着输入N组数据每组包括一行字符串，将其翻译为另一个星球的数字。
AAAAAccepted code：
#define HAVE_STRUCT_TIMESPEC
#include<bits/stdc++.h>
using namespace std;
char a[][]={"","tam","hel","maa","huh","tou","kes","hei","elo","syy","lok","mer","jou"};
char b[][]={"tret","jan","feb","mar","apr","may","jun","jly","aug","sep","oct","nov","dec"};
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n;
cin>>n;
cin.ignore();
for(int q=;q<=n;++q){
string s;
getline(cin,s);
if(s[]>=''&&s[]<=''){
int temp=;
for(int j=;j<s.size();++j){
temp*=;
temp+=s[j]-'';
}
int x=temp/;
int y=temp%;
if(x&&y)
cout<<a[x]<<" "<<b[y]<<"\n";
else if(x)
cout<<a[x]<<"\n";
else
cout<<b[y]<<"\n";
}
else{
if(s[]==' '&&s[]!=){
char x[]={},y[]={};
for(int i=;i<;++i)
x[i]=s[i];
for(int i=;i<;++i)
y[i-]=s[i];
int pos=;
for(int i=;i<=;++i){
if(strcmp(a[i],x)==){
pos=i;
break;
}
}
int pos2=;
for(int i=;i<=;++i){
if(strcmp(b[i],y)==){
pos2=i;
break;
}
}
int temp=pos*+pos2;
cout<<temp<<"\n";
}
else if(s[]!=&&s[]==)
cout<<"0\n";
else{
char x[]={};
for(int i=;i<;++i)
x[i]=s[i];
int pos=;
for(int i=;i<=;++i)
if(strcmp(a[i],x)==){
pos=i;
break;
}
int pos2=;
for(int i=;i<=;++i)
if(strcmp(b[i],x)==){
pos2=i;
break;
}
int temp=pos*+pos2;
cout<<temp<<"\n";
}
}
}
return ;
}