也许我很困,但在什么情况下会发生以下情况？

let foo;

page
  .evaluate(() => {
    // return works... but not closure assignment

    // doesn't work
    foo = 'foo';

    // works
    return 'bar';
  })
  .then(bar => {
    console.log('foobar', foo, bar);
    // > foobar undefined bar
  });

这是在使用木偶操纵者的摩卡测试中发生的

更新：完整的代码

节点9.11.2

/* global describe, it, before, after */

const fs = require('fs-extra');
const path = require('path');
const assert = require('assert');
const puppeteer = require('puppeteer');
const sleep = require('shleep');

const extPath = path.resolve(__dirname, '..', 'build');
const { name } = fs.readJSONSync(path.resolve(extPath, 'manifest.json'));

// Access chrome object in Extensions
// https://github.com/GoogleChrome/puppeteer/issues/2878

describe('chrome extension', () => {
  let browser;
  let extensionPage;

  before(async function() {
    this.timeout(90 * 1000);

    // start puppeteer
    browser = await puppeteer.launch({
      headless: false,
      args: [
        `--disable-extensions-except=${extPath}`,
        `--load-extension=${extPath}`
      ]
    });

    // poll instead of hope this is enough time?
    const EXT_LOAD_DELAY = 100;
    await sleep(EXT_LOAD_DELAY);

    const targets = await browser.targets();

    const extensionTarget = targets.find(
      ({ _targetInfo }) =>
        _targetInfo.type === 'background_page' && _targetInfo.title === name
    );

    const page = await extensionTarget.page();

    let foo;

    page
      .evaluate(() => {
        // return works... but not closure assignment

        // doesn't work
        foo = 'foo';

        // doesn't log
        console.log('foo', foo);

        // works
        return 'bar';
      })
      .then(bar => {
        console.log('foobar', foo, bar);
        // > foobar undefined bar
      });
  });

  it('should load', async () => {
    assert(true);
  });
});

测试截图

解决方法:

puppeteer中的evaluate方法没有您在代码中本地或全局声明的变量概念.传递给evaluate方法的函数是要在页面上下文中执行的函数(即在浏览器中).由于foo未在页面上下文中声明,因此无法访问它,因此无法更新其值.

所以要逐步执行代码：

let foo;

await page.evaluate(() => {
  foo = 'foo';  // Since no variable foo is known to the evaluate method in the context of your page
                // this line , effectively, assigns a new variable called foo with a value 'foo' which
                // is then lost once the method has completed since its value is never returned.

  return 'bar'; // This value is returned from the method and is therefore retained below
})
.then(bar => {
  console.log('foobar', foo, bar);
  // foobar is output as expected since you've hardcoded it

  // foo is now referring to the global foo you declared earlier but since you have used `let` and not
  // assigned it any value, it is output as 'undefined'

  // bar is the value you returned from your 'evaluate' function and is therefore output as 'bar' as
  // expected in the console log.
});

如果你想使用evaluate更新你的变量foo,你必须这样做：

let foo;
foo = await page.evaluate(() => {
  return 'foo'
});
console.log(foo); // Now outputs 'foo' as expected

但是,您可以将变量注入到evaluate方法中并更新它们的值(如果您愿意),例如：

let foo = 'foo'
console.log(foo); // Outputs 'foo' as expected
foo = await page.evaluate((injectedFoo) => {
  return `new${injectedFoo}`;
}, foo);
console.log(foo); // Outputs 'newfoo'

那么这里发生的是你通过在方法声明的末尾将它作为参数传递,将变量foo注入到evaluate方法中. evaluate方法现在包含一个变量(为了清楚起见,我称之为injectFoo),它携带foo变量的原始值.

然后我将附加到开头的字符串new返回到foo变量字符串,并在控制台中输出该字符串的最终值.

我希望这有助于解释评估方法的工作原理！