如何使用jshell运行java应用程序？它应该能够指定类路径并调用java命令并传递一些参数,如bash do,例如,

#!/bin/bash
$ARGS=...
$CLASSPATH=...
java -cp $CLASSPATH $ARGS com.example.MyApp

更新：
我认为需要运行时或进程的包装器,例如,

jshell> private String executeCommand(String command) {
   ...>
   ...>         StringBuffer output = new StringBuffer();
   ...>
   ...>         Process p;
   ...>         try {
   ...>             p = Runtime.getRuntime().exec(command);
   ...>             p.waitFor();
   ...>             BufferedReader reader =
   ...>                             new BufferedReader(new InputStreamReader(p.getInputStream()));
   ...>
   ...>                         String line = "";
   ...>             while ((line = reader.readLine())!= null) {
   ...>                 output.append(line + "\n");
   ...>             }
   ...>
   ...>         } catch (Exception e) {
   ...>             e.printStackTrace();
   ...>         }
   ...>
   ...>         return output.toString();
   ...>
   ...>     }
|  Created method executeCommand(String)

jshell> String out =executeCommand("java --version");
out ==> "java 9.0.4\nJava(TM) SE Runtime Environment (bui ... d 9.0.4+11, mixed mode)\n"

jshell> System.out.println(out);
java 9.0.4
Java(TM) SE Runtime Environment (build 9.0.4+11)
Java HotSpot(TM) 64-Bit Server VM (build 9.0.4+11, mixed mode)

解决方法:

对于在jshell中运行任何应用程序,首先在开始时将类路径设置为jshell.

例：

jshell -class-path /Users/sree/Desktop/libs/jettison-1.0.1.jar 

然后将类导入到运行的环境中

import org.codehaus.jettison.json.JSONObject;

这会将所需的类导入到环境中.

现在运行所需的应用程序.就我而言,我进入了

String myString = new JSONObject().put("JSON", "Hello, World!").toString()

并得到了输出

myString ==> "{\"JSON\":\"Hello, World!\"}"

回答传递命令行参数的问题.你必须用所有的值来启动课程.

Test instance = new Test("data","data1")