Sum of odd numbers

Given the triangle of consecutive odd numbers:
给定连续奇数的三角形：

             1
          3     5
       7     9    11
   13    15    17    19
21    23    25    27    29
...

Calculate the sum of the numbers in the nth row of this triangle (starting at index 1) e.g.: (Input --> Output)
计算此三角形第n行中的数字之和（从索引1开始），例如：（输入–>输出）

1 -->  1
2 --> 3 + 5 = 8

solution:

class RowSumOddNumbers {
    public static int rowSumOddNumbers(int n) {
      return 0;
    }
}

Sample Tests:

import static org.junit.Assert.*;
import org.junit.Test;

public class RowSumOddNumbersTest {

    @Test
    public void test1() {
        assertEquals(1, RowSumOddNumbers.rowSumOddNumbers(1));
        assertEquals(74088, RowSumOddNumbers.rowSumOddNumbers(42));
    }
}

解决方法：

class RowSumOddNumbers {
    public static int rowSumOddNumbers(int n) {
      int sum=0;
      for(int i=1;i<=n;i++){
        sum=i*(int)(Math.pow(i, 2));
      }
	return sum;
    }
}