我需要获取应用的每日报告.

报告应该告诉我访问事件页面的次数以及每个类别销售的票数.所有这些都应按天分组在一行中,如下所示：

Date        | Category A | Category B | Category C | Visits
'2017-03-10'|         10 |          2 |          8 |     30

使用序列表我能够按天分组结果,但我能做的最好的是每天为每个类别排一行,即,如果我有3个类别,我每天得到3行.

Fiddle

解决方法:

如果事先已知固定类别的数量,这只是对现有解决方案的一些条件求和…并通过子查询添加访问所需的任何逻辑：

SELECT
    date,
    sum(CASE WHEN `categoryId`=1 THEN `ticketCount` END) AS `Category A`,
    sum(CASE WHEN `categoryId`=2 THEN `ticketCount` END) AS `Category B`,
    sum(CASE WHEN `categoryId`=3 THEN `ticketCount` END) AS `Category C`,
    (SELECT  count(id) FROM event_page_visits 
      WHERE event_id = 1 and date(created_at) = date) AS `Visits`
FROM
(
    select 
      `list_of_dates`.`date` as `date`, `ticket_categories`.`id` as `categoryId`, `ticket_categories`.`name` as `categoryName`, count(tickets.id) as ticketCount 
    from ( 
      SELECT DATE_ADD('2017-03-10', INTERVAL seq.seq DAY) AS DATE FROM seq_0_to_999 AS seq WHERE DATE_ADD('2017-03-10', INTERVAL seq.seq DAY) <= '2017-03-14' 
    ) as list_of_dates 
    cross join 
      `ticket_categories` 
    left join 
      `tickets` on 
        `tickets`.`ticket_category_id` = `ticket_categories`.`id` and 
        `tickets`.`created_at` >= `list_of_dates`.`date` and 
        `tickets`.`created_at` < list_of_dates.date + INTERVAL 1 DAY
    where 
      `ticket_categories`.`event_id` = 1
    group by 
      `date`, `ticket_categories`.`id`
) AS q
GROUP BY 
   `date`
order by 
  `date` asc ;

而你只是得到：

|       date | Category A | Category B | Category C | Visits |
|------------|------------|------------|------------|--------|
| 2017-03-10 |          4 |          3 |          2 |     10 |
| 2017-03-11 |          0 |          0 |          0 |      2 |
| 2017-03-12 |          1 |          1 |          0 |      3 |
| 2017-03-13 |          0 |          0 |          3 |      6 |
| 2017-03-14 |          0 |          0 |          0 |      0 |

Fiddle.