//求两个数中不同的位的个数

#include <stdio.h>

int count_different(int a, int b)

{

	int count = 0;

	int c = a^b;        //a,b中不同的位即为1

	while (c)

	{

		count++;

		c = c&(c - 1);  //把c中最后一个1去掉

	}

	return count;

}

int main()

{

	printf("%d\n", count_different(3,8));   //3

	printf("%d\n", count_different(0, 6));  //2

	printf("%d\n", count_different(-1,1));  //31

	return 0;

}