[leetcode]Pascal's Triangle @ Python

原题地址:https://oj.leetcode.com/problems/pascals-triangle/

题意:

Given numRows, generate the first numRows of Pascal's triangle.

For example, given numRows = 5,
Return

[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
]

解题思路:杨辉三角的求解。

代码:

class Solution:
# @return a list of lists of integers
def generate(self, numRows):
if numRows == 0:
return []
if numRows == 1:
return [[1]]
if numRows == 2:
return [[1], [1, 1]]
if numRows > 2:
list = [[] for i in range(numRows)]
for i in range(0, numRows):
list[i] = [1 for j in range(i + 1)]
for i in range(2, numRows):
for j in range(1, i):
list[i][j] = list[i - 1][j - 1] + list[i - 1][j]
return list
上一篇:C 函数参数 char **s与char *s[]


下一篇:清除代码中的svn文件。