逻辑操作符

身份操作符 is

a = ['AAA', 3, None]

b = ['AAA', 3, None]

a is b #False

b = a

a is b #True

身份比较速度快，原因是对直接对内存地址进行比较，所以内容相同的俩个变量结果却是false。

a = None

a is None #True

比较操作符

这里只要注意一点

0 <= a <= 10

这种结链比较是可以的，夸张一点

a < b < c < e < d

逻辑操作符

逻辑操作符：and or not

其中 and or 都使用short-circuit逻辑实现

5 and 2 #2

2 and 5 #5

5 and 2 and 3 #3

5 or 2 #5

2 or 5 #2

2 or 3 or 5 #2

2 or 3 and 5 #2

2 and 3 or 5 #3

2 or 3 and 4 and 5 and 6 and 7 #2

2 or 3 and 4 and 0 #2

0 or 3 and 4 and 5 #5

True and 1 # 1

1 and True # True

还可以得出结论， and 的优先级大于 or

算术操作符

a = 1

a += 8

a = a + 8

这里需要记住的是，python中，int数据类型是固定的，一旦赋值就不能改变。因此，对固定的对象使用增强的赋值操作符时，实际上是创建一个对象来存储结果，之后，目标对象重新绑定。所以上面的:a+=8语句执行的时候，python 会计算a+8，将所得的结果9存储到新的int对象，之后将a重新绑定为引用这个新的int对象（如果a原来引用的原始对象没有其他对象引用，就会进入垃圾收集流程）。

第二 a+=8 与 a = a + 8 并不一致，这个没怎么明白。

特殊用法：

name = 'xxx'

name + 'ccc' #xxxccc

name += 'ccc' #xxx ccc

与int一样 字符串也是固定的，所以流程和上述相同，

不过列表在python中是可变的

a = ['a', 'b', 'c']

a += 'ddd' #['a', 'b', 'c', 'd', 'd', 'd']

a += ['ddd'] #['a', 'b', 'c', 'd', 'd', 'd', 'ddd']

a += 5 #报错

列表 += 右边的操作数必须是 iterable 对象

题目

1.生成数字

import random

digits = [7, 1, 9, 4, 2, 8, 3, 0, 6]

Digits = [[random.randint(1, 1000) for j in range(7)] for i in range(10)]

try:

    row = 0

    while row < 7:

        line = ''

        column = 0

        while column < len(digits):

            number = int(digits[column])

            digit = Digits[number]

            line += str(digit[row]) + ' '

            column += 1

        print(line)

        row += 1

except IndexError:

    print('usage: <number>')

except ValueError as err:

    print(err, 'in', digits)

2.循环输入数字输出长度，和，最大最小值，平均值

try:

    digits = []

    while True:

        a = input('enter a number or Enter to finish: ')

        if not a and a != 0:

            break

        else:

            digits.append(int(a))

    print('numbers: ', digits)

    print('count = ', len(digits), ' sum = ', sum(digits),

    ' lowest = ', min(digits), ' highest = ', max(digits),

          'mean = ', sum(digits) / len(digits))

except ValueError as err:

    print(err, 'in', a)

1. 超级超级巨大巨大罪过的诗

import random

article = ['a', 'the', 'this', 'that']

theme = ['cat', 'fish', 'dog', 'pig', 'car', 'house', 'tree']

verb = ['flied', 'walked', 'runned', 'smiled', 'jumped']

adv = ['loudly', 'quietly', 'well', 'badly']

try:

    count = 0

    while count < 5:

        line = article[random.randint(0, len(article) - 1)] + ' ' +\

               theme[random.randint(0, len(theme) - 1)] + ' ' +\

               verb[random.randint(0, len(verb) - 1)] + ' ' +\

               adv[random.randint(0, len(adv) - 1)]

        print(line)

        count += 1

except IndexError:

    print('error index')

4.用户指定行数

import random

article = ['a', 'the', 'this', 'that']

theme = ['cat', 'fish', 'dog', 'pig', 'car', 'house', 'tree']

verb = ['flied', 'walked', 'runned', 'smiled', 'jumped']

adv = ['loudly', 'quietly', 'well', 'badly']

try:

    count = 0

    uplimit = int(input('the rows you need between 1 and 10: '))

    if not uplimit or not 1<= uplimit <= 10:

        uplimit = 5

    while count < uplimit:

        line = article[random.randint(0, len(article) - 1)] + ' ' +\

               theme[random.randint(0, len(theme) - 1)] + ' ' +\

               verb[random.randint(0, len(verb) - 1)] + ' ' +\

               adv[random.randint(0, len(adv) - 1)]

        print(line)

        count += 1

except IndexError:

    print('error index')

5.自制排序程序（从小到大）

import random

number = [random.randint(1, 99) for i in range(10)]

print(number)

try:

    length = len(number)

    for i in range(length - 1):

        for j in range(i + 1, length):

            if number[i] > number[j]:

                number[i], number[j] = number[j], number[i]

    print(number)

except IndexError:

    print('index error')

很粗暴的一种排序方式，不过不计较这么多了，简单易懂就行。

。。。