Emag eht htiw Em Pleh
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 2806 | Accepted: 1865 |
Description
This problem is a reverse case of the problem 2996. You are given the output of the problem H and your task is to find the corresponding input.
Input
according to output of problem 2996.
Output
according to input of problem 2996.
Sample Input
White: Ke1,Qd1,Ra1,Rh1,Bc1,Bf1,Nb1,a2,c2,d2,f2,g2,h2,a3,e4
Black: Ke8,Qd8,Ra8,Rh8,Bc8,Ng8,Nc6,a7,b7,c7,d7,e7,f7,h7,h6
Sample Output
+---+---+---+---+---+---+---+---+
|.r.|:::|.b.|:q:|.k.|:::|.n.|:r:|
+---+---+---+---+---+---+---+---+
|:p:|.p.|:p:|.p.|:p:|.p.|:::|.p.|
+---+---+---+---+---+---+---+---+
|...|:::|.n.|:::|...|:::|...|:p:|
+---+---+---+---+---+---+---+---+
|:::|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|...|:::|...|:::|.P.|:::|...|:::|
+---+---+---+---+---+---+---+---+
|:P:|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|.P.|:::|.P.|:P:|...|:P:|.P.|:P:|
+---+---+---+---+---+---+---+---+
|:R:|.N.|:B:|.Q.|:K:|.B.|:::|.R.|
+---+---+---+---+---+---+---+---+
#include<cstdio>
#include <cstring>
using namespace std;
char maz[17][34];
int mp[255];
char cell[2][3][6]={
{
"+---+",
"|:::|",
"+---+",
},
{
"+---+",
"|...|",
"+---+",
}
};
void dye(int x,int y){
for(int i=0;i<3;i++){
for(int j=0;j<5;j++){
maz[2*x+i][4*y+j]=cell[(x+y)&1][i][j];
}
}
}
void clearchess(){
memset(maz,0,sizeof(maz));
for(int i=0;i<8;i++){
for(int j=0;j<8;j++){
dye(i,j);
}
}
}
char buff[1024];
void subinsrt(int x,int y,char ch){
x--;
maz[2*x+1][4*y+2]=ch;
}
void insrt(bool upc){
int len=strlen(buff);
char use;
for(int i=0;i<len;){
int j;
for( j=i;j<len&&buff[j]!=',';j++){}
if(j-i==3)use=buff[i];
else use='P';
if(upc)subinsrt(buff[j-1]-'0',mp[buff[j-2]],use);
else subinsrt(buff[j-1]-'0',mp[buff[j-2]],use-'A'+'a');
i=j+1;
// for(int i=0;i<17;i++)puts(maz[i]);
}
}
int main(){
for(int i=0;i<26;i++)mp[i+'a']=i;
clearchess();
scanf("%s",buff);
scanf("%s",buff);
insrt(true);
scanf("%s",buff);
scanf("%s",buff);
insrt(false);
for(int i=16;i>=0;i--)puts(maz[i]);
return 0;
}