我正在读取文本文件中的行形式,然后每行执行操作.由于文本文件的大小和每个动作的时间500 =>.秒.我希望能够查看进度,但不确定从哪里开始.

这是我正在使用的示例脚本,该如何编写呢？

import os

tmp = "test.txt"
f = open(tmp,'r')

for i in f:
    ip = i.strip()
    os.system("ping " + ip + " -n 500")

f.close()

test.txt：

10.1.1.1
10.1.1.2
10.2.1.1
10.2.1.1

解决方法:

这是一个方便的模块：progress_bar.

它足够简短.阅读有关实现自己的想法的资源.

我希望这是一段非常简单的代码,可以使事情变得更清楚：

import time, sys

# The print statement effectively treats '\r' as a newline, 
# so use sys.stdout.write() and .flush() instead ...
def carriage_return_a():
    sys.stdout.write('\r')
    sys.stdout.flush()

# ... or send a terminal control code to non-windows systems
# (this is what the `progress_bar` module does)
def carriage_return_b():
    if sys.platform.lower().startswith('win'):
        print '\r'
    else:
        print chr(27) + '[A'

bar_len = 10
for i in range(bar_len + 1):
    # Generate a fixed-length string of '*' and ' ' characters
    bar = ''.join(['*'] * i + [' '] * (bar_len - i))

    # Insert the above string and the current value of i into a format
    # string and print, suppressing the newline with a comma at the end
    print '[{0}] {1}'.format(bar, i),

    # Write a carriage return, sending the cursor back to the beginning
    # of the line without moving to a new line. 
    carriage_return_a()

    # Sleep
    time.sleep(1)

正如其他人所观察到的那样,您仍然需要知道文件中的总行数才能拥有非常有意义的进度条.最简单的方法是读取整个文件以获得行数.但这很浪费.

将其整合到一个简单的类中并不是一件容易的事……现在您可以创建进度条,并在感兴趣的值发生变化时对其进行update().

class SimpleProgressBar(object):
    def __init__(self, maximum, state=0):
        self.max = maximum
        self.state = state

    def _carriage_return(self):
        sys.stdout.write('\r')
        sys.stdout.flush()

    def _display(self):
        stars = ''.join(['*'] * self.state + [' '] * (self.max - self.state))
        print '[{0}] {1}/{2}'.format(stars, self.state, self.max),
        self._carriage_return()

    def update(self, value=None):
        if not value is None:
            self.state = value
        self._display()

spb = SimpleProgressBar(10)
for i in range(0, 11):
    time.sleep(.3)
    spb.update(i)