【leetcode】867 - Transpose Matrix

【题干描述】

Given a matrix A, return the transpose of A.

The transpose of a matrix is the matrix flipped over it's main diagonal, switching the row and column indices of the matrix.(一矩阵A,返回其转置)

【思路】

  • 直接处理,A[i][j]的值赋值给output[j][i].

【python代码】

 input = [[1, 2, 3], [4, 5, 6]]
row = len(input)
col = len(input[0]) output = [[None]*row for _ in range(col)] for j in range(col):
for i in range(row):
output[j][i] = input[i][j]
print output

【所用python点】

  • range()和xrange()的区别:https://www.cnblogs.com/Sinkinghost/p/9320070.html
  • [[None]*row for _ in range(col)] 的 “_” 其实可以用 任意变量替换。
  • [None]*row 的结果是[None, None, None]
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