说明：layui中用jquery 中的选择器例如$('#id').change(function(){})发现不起作用

layui操作：lay-felter标识操作哪个个select

<select name="shop_id" lay-verify="required" lay-search="" lay-filter="select_shop">
   <option value="0">请选择门店</option>
   <option value="1">门店1</option>
   <option value="1">门店2</option>
</select>

layui.use(['form','layer','table','jquery'],function(){

var form = layui.form;

form.on('select(select_shop)', function(data){
   $scope.select_shop = data.value;
   var html = '<option value="0">请选择摄影师</option>';

   $.post("{:url('/json/getShopCameraman')}", {
      shop_id: $scope.select_shop
   }, function(data) {
      $(data.data).each(function(index, item) {
         html += '<option value="' + item.id + '">' + item.name + '</option>';
      });
      $("#select_cameraman").html(html);
      form.render('select'); //这个很重要,没有这个新的option不会显示
   }, 'json');
});

}）