#include<iostream>

 #include<cstdio>

 #include<cmath>

 #include<ctime>

 using namespace std;

 #define eps 1e-3

 #define pi  acos(-1.0)

 #define POI 15            //独立跑POI次，找其中最小的        tp[1..POI]是随机的初值

 #define RUN 40            //迭代次数，本题中即点(tx,ty)向RUN个方向发散

 int X,Y,N;

 double ans;

 int ansi;

 struct

 {

     double x,y;

 }tp[],hol[];

 double sol[];

 double dist(double x1,double y1,double x2,double y2)

 {

     return(sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)));

 }

 double dis(double x,double y)

 {

     double tmp=0.000;

     for(int i=;i<=N;i++)

     {

         double tx=hol[i].x,ty=hol[i].y;

         tmp=max(tmp,dist(tx,ty,x,y));

     }

     return tmp;

 }

 void sa()

 {

     for(int i=;i<=POI;i++)

     {

         tp[i].x=(rand()%+)/1000.0*X;

         tp[i].y=(rand()%+)/1000.0*Y;

         sol[i]=dis(tp[i].x,tp[i].y);

         //printf("%.1f~%.1f=%.1f\n",tp[i].x,tp[i].y,sol[i]);

     }

     double step=1.0*max(X,Y)/sqrt(1.0*N);

     while(step>eps)

     {

         for(int i=;i<=POI;i++)

         {

             double kx=tp[i].x,ky=tp[i].y;

             double tx=kx,ty=ky;

             for(int j=;j<RUN;j++)

             {

                 double angle=(rand()%+)/1000.0**pi;

                 kx=tx+cos(angle)*step;

                 ky=ty+sin(angle)*step;

                 if((kx>X)||(ky>Y)||(kx<)||(ky<))    continue;

                 double tmp=dis(kx,ky);

                 if(tmp<sol[i])

                 {

                     tp[i].x=kx;    tp[i].y=ky;

                     sol[i]=tmp;

                 }

             }

         }

         step*=0.80;

     }

 }

 int main()

 {

     srand(time(NULL));

     while(cin>>X>>Y>>N)

     {

         for(int i=;i<=N;i++)

             cin>>hol[i].x>>hol[i].y;

         sa();

         ans=(X*X+Y*Y)*100.0;

         for(int i=;i<=POI;i++)

         {

             //printf("AA: %.1f~%.1f=%.1f\n",tp[i].x,tp[i].y,sol[i]);

             if(sol[i]<ans)

             {

                 ans=sol[i];

                 ansi=i;

             }

         }

         printf("(%.1f,%.1f).\n",tp[ansi].x,tp[ansi].y);

         printf("%.1lf\n",ans);

     }

     return ;

 }