将json转换为Java Object – 将属性设置为Null

我正在尝试将Json转换为Java对象.我有一个名为’result’的String,我想将其转换为类对象为TransferRecord.java的Java对象

这是我用作输入的字符串的一部分.

{
  "TransferRecord": {
    "TransferId": {
      "TransferRef": "string",
      "DistributorRef": "string"
    },
    "SkuCode": "string",
    "Price": {
      "CustomerFee": 0,
      "DistributorFee": 0,
      "ReceiveValue": 0,
      "ReceiveCurrencyIso": "string",
      "ReceiveValueExcludingTax": 0,
      "TaxRate": 0,
      "TaxName": "string",
      "TaxCalculation": "string",
      "SendValue": 0,
      "SendCurrencyIso": "string"
    },
    "CommissionApplied": 0,
    "StartedUtc": "2019-01-31T10:10:20.527Z",
    "CompletedUtc": "2019-01-31T10:10:20.527Z",
    "ProcessingState": "string",
    "ReceiptText": "string",
    "ReceiptParams": {},
    "AccountNumber": "string"
  },
  "ResultCode": 0,
  "ErrorCodes": [
    {
      "Code": "string",
      "Context": "string"
    }
  ]
}

这是TransferRecord类.我检查了json映射,它们完全相同.请注意,类中有更多字段,但我只是粘贴了它的一部分.输入字符串和java类中的属性数相同.

public class TransferRecord   {
  @JsonProperty("TransferId")
  private TransferId transferId = null;

  @JsonProperty("SkuCode")
  private String skuCode = null;

  @JsonProperty("Price")
  private Price price = null;

  @JsonProperty("CommissionApplied")
  private BigDecimal commissionApplied = null;

  @JsonProperty("StartedUtc")
  private Date startedUtc = null;

  @JsonProperty("CompletedUtc")
  private Date completedUtc = null;

  @JsonProperty("ProcessingState")
  private String processingState = null;

  @JsonProperty("ReceiptText")
  private String receiptText = null;

  @JsonProperty("ReceiptParams")
  private Map<String, String> receiptParams = null;

  @JsonProperty("AccountNumber")
  private String accountNumber = null;

  public TransferRecord transferId(TransferId transferId) {
    this.transferId = transferId;
    return this;
  }
}

以下是我用于转换的代码.请注意,这三段代码将起到相同的作用,我分别尝试了它们.

ObjectMapper mapper = new ObjectMapper();

//1 TransferRecord objTransRecord = mapper.readValue(result, TransferRecord.class);

//2 TransferRecord objTransRecord = mapper.readerWithView(TransferRecord.class).forType(TransferRecord.class).readValue(result);

//3 TransferRecord objTransRecord = mapper.readerFor(TransferRecord.class).readValue(result);

问题是当我尝试创建对象时,即使String中有相应的数据,所有三种方法中的每个值都设置为null.有人可以指出我在这里做错了什么吗?

提前致谢.

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