A. Boredom
Time Limit: 20 Sec
Memory Limit: 256 MB
题目连接
http://codeforces.com/contest/455/problem/A
Description
Given a sequence a consisting of n integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it ak) and delete it, at that all elements equal to ak + 1 and ak - 1 also must be deleted from the sequence. That step brings ak points to the player.
Alex is a perfectionist, so he decided to get as many points as possible. Help him.
Input
The first line contains integer n (1 ≤ n ≤ 105) that shows how many numbers are in Alex's sequence.
The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 105).
Output
Print a single integer — the maximum number of points that Alex can earn.
Sample Input
2
1 2
Sample Output
2
HINT
题意
给你n个数，你每次可以选择删除去一个数x，但是等于x+1和等于x-1的数都得删去
你每一次操作可以得x分
题解：
dp，dp[i]表示到i后能够得到的最大分数
dp[i]=max(dp[i-1],dp[i-2]+a[i-1]*(i-1));
代码：
#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
#include <map>
#include <stack>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define test freopen("test.txt","r",stdin)
#define maxn 2000001
#define mod 10007
#define eps 1e-5
const int inf=0x3f3f3f3f;
const ll infll = 0x3f3f3f3f3f3f3f3fLL;
inline ll read()
{
ll x=,f=;char ch=getchar();
while(ch<''||ch>''){if(ch=='-')f=-;ch=getchar();}
while(ch>=''&&ch<=''){x=x*+ch-'';ch=getchar();}
return x*f;
}
//************************************************************************************** ll a[],dp[];
int main()
{
int n=read();
for(int i=;i<n;i++)
{
int x=read();
a[x]++;
}
for(int i=;i<;i++)
dp[i]=max(dp[i-],dp[i-]+a[i-]*(i-));
cout<<dp[]<<endl;
}