// 判断是否无限循环小数 export function f (n) { if (n === 1) return false else if (n % 2 === 0) { return f(n / 2) } else if (n % 5 === 0) { return f(n / 5) } else return true } // 除法函数 export function accDiv (arg1, arg2) { let t1, t2 try { t1 = arg1.toString().split('.')[1].length } catch (e) { t1 = 0 } try { t2 = arg2.toString().split('.')[1].length } catch (e) { t2 = 0 } const r1 = Number(arg1.toString().replace('.', '')) const r2 = Number(arg2.toString().replace('.', '')) const n = (t1 >= t2) ? t1 : t2 let result = r1 / r2 if (f(r2)) { result = result.toFixed(n > 3 ? n : 3) } return result * Math.pow(10, t2 - t1) } // 乘法函数 export function accMul (arg1, arg2) { let m = 0 const s1 = arg1.toString() const s2 = arg2.toString() m += s1.split('.')[1] ? s1.split('.')[1].length : 0 m += s2.split('.')[1] ? s2.split('.')[1].length : 0 return Number(s1.replace('.', '')) * Number(s2.replace('.', '')) / Math.pow(10, m) } // 加法函数 export function accAdd (arg1, arg2) { let r1, r2 try { r1 = arg1.toString().split('.')[1].length } catch (e) { r1 = 0 } try { r2 = arg2.toString().split('.')[1].length } catch (e) { r2 = 0 } const m = Math.pow(10, Math.max(r1, r2)) return (arg1 * m + arg2 * m) / m } // 减法函数 export function Subtr (arg1, arg2) { let r1, r2 try { r1 = arg1.toString().split('.')[1].length } catch (e) { r1 = 0 } try { r2 = arg2.toString().split('.')[1].length } catch (e) { r2 = 0 } const m = Math.pow(10, Math.max(r1, r2)) const n = (r1 >= r2) ? r1 : r2 return Number(((arg1 * m - arg2 * m) / m).toFixed(n)) }