利用python代码获取文件特定的内容,并保存为文档

说明:有段时间需要读取上百个文件的单点能(sp),就写了下面的代码(计算化学狗努力转行中^-^)

import os.path
import re # 1 遍历指定目录,显示目录下的所有文件名
def each_file(file_path):
path_dir = os.listdir(file_path)
  # 将得到列表内的文件排序(因为自己要读取的文件类型是1.out,2.out,3.out......这样的,所以可以切片排序)
path_dir.sort(key = lambda x: x.split('.'[0]))
for one_dir in path_dir:
print(one_dir)
one_dir_path = os.path.join('%s/%s' % (file_path, one_dir))
if os.path.isfile(one_dir_path):
read_file(one_dir_path)
continue
each_file(one_dir_path) # 2 匹配出所需的内容,并写入指定文档
def read_file(filename):
fopen = open(filename, 'r')
fwrite = open("sp.txt", 'a')
file_read = fopen.read()
ret = re.findall(r"\\(HF=.+?)\\", file_read)
if not ret:
fwrite.write(filename + "计算结果有误" + "\n")
for sp in ret:
fwrite.write(filename + sp + "\n")
fwrite.close()
fopen.close() if __name__ == "__main__":
# 清除sp.txt内存在的内容
if os.path.exists('/home/python/Desktop/rw/sp.txt'): # 此路径为存放此段代码的目录
fwrite = open("sp.txt", 'w')
fwrite.truncate()
filenames = input("请输入文件的绝对路径:")
each_file(filenames)

  

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