需要有关Linux Bash脚本的帮助.基本上,当运行脚本时,要求用户提供三组数字,然后计算输入的数字并找到平均值.

#!/bin/bash
echo "Enter a number: "
read a
   while [ "$a" = $]; do

echo "Enter a second set of numbers: "
read b
b=$
   if [ b=$]

我错了吗？

解决方法:

仍然不确定你想要的是什么.但我认为你可以循环3次.然后每次迭代都会获得一组数字,然后将它们相加并跟踪您拥有的数量.如下所示. (注意$numbers和$sum自动初始化为0)

#!/bin/bash    
sum=0
numbers=0
for a in {1..3}; do
  read -p $'Enter a set of numbers:\n' b
  for j in $b; do
    [[ $j =~ ^[0-9]+$]] || { echo "$j is not a number" >&2 && exit 1; } 
    ((numbers+=1)) && ((sum+=j))
  done
done

((numbers==0)) && avg=0 || avg=$(echo "$sum / $numbers" | bc -l)
echo "Sum of inputs = $sum"
echo "Number of inputs = $numbers"
printf "Average input = %.2f\n" $avg                               

示例输出将是

Enter a set of numbers: 
1 2 3
Enter a set of numbers: 
1 2 3
Enter a set of numbers: 
7
Sum of inputs = 19
Number of inputs = 7
Average input = 2.71