集合运算符之全集、交集、补集【weber出品必属精品】

  1. 集合的概念

    与数学中的全集、交集、补集的概念是一样的

  2. 常用的集合运算符

    集合运算符的作用:把两个查询构造为一个联合查询

    1. 全集:求连个查询的全集

    union all:将两个查询的所有数据全部列出,不进行排序,不去掉重复的部分

    SQL> create table t1 as select * from emp where deptno in (,);
    
    Table created.
    
    SQL> create table t2 as select * from emp where deptno in (,);
    
    Table created.
    SQL> select * from t1; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
    SMITH CLERK -DEC-
    JONES MANAGER -APR-
    CLARK MANAGER -JUN-
    SCOTT ANALYST -APR-
    KING PRESIDENT -NOV-
    ADAMS CLERK -MAY-
    FORD ANALYST -DEC-
    MILLER CLERK -JAN- rows selected. SQL> select * from t2; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
    SMITH CLERK -DEC-
    ALLEN SALESMAN -FEB-
    WARD SALESMAN -FEB-
    JONES MANAGER -APR-
    MARTIN SALESMAN -SEP-
    BLAKE MANAGER -MAY-
    SCOTT ANALYST -APR-
    TURNER SALESMAN -SEP-
    ADAMS CLERK -MAY-
    JAMES CLERK -DEC-
    FORD ANALYST -DEC- rows selected. SQL> select * from t1
    union all
    select * from t2; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
    SMITH CLERK -DEC-
    JONES MANAGER -APR-
    CLARK MANAGER -JUN-
    SCOTT ANALYST -APR-
    KING PRESIDENT -NOV-
    ADAMS CLERK -MAY-
    FORD ANALYST -DEC-
    MILLER CLERK -JAN-
    SMITH CLERK -DEC-
    ALLEN SALESMAN -FEB-
    WARD SALESMAN -FEB-
    JONES MANAGER -APR-
    MARTIN SALESMAN -SEP-
    BLAKE MANAGER -MAY-
    SCOTT ANALYST -APR-
    TURNER SALESMAN -SEP-
    ADAMS CLERK -MAY-
    JAMES CLERK -DEC-
    FORD ANALYST -DEC- rows selected.

    union:将两个查询的所有数据进行显示,但是重复的部分只显示一次,而且要按照第一个查询的第一列进行升序排序

    SQL> select * from t1
    union
    select * from t2; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
    SMITH CLERK -DEC-
    ALLEN SALESMAN -FEB-
    WARD SALESMAN -FEB-
    JONES MANAGER -APR-
    MARTIN SALESMAN -SEP-
    BLAKE MANAGER -MAY-
    CLARK MANAGER -JUN-
    SCOTT ANALYST -APR-
    KING PRESIDENT -NOV-
    TURNER SALESMAN -SEP-
    ADAMS CLERK -MAY-
    JAMES CLERK -DEC-
    FORD ANALYST -DEC-
    MILLER CLERK -JAN- rows selected.

    union all与union的性能哪个更高?

    union all性能更高:因为union all 不进行排序,也不去重

    2. 交集:INTERSECT

    SQL> select * from t1
    intersect
    select * from t2; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
    SMITH CLERK -DEC-
    JONES MANAGER -APR-
    SCOTT ANALYST -APR-
    ADAMS CLERK -MAY-
    FORD ANALYST -DEC-

    3. 补集:MINUS
    查询select * from e2的补集:

    SQL> select * from t1
    minus
    select * from t2; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
    ---------- ---------- --------- ---------- --------- ---------- ---------- ----------
    CLARK MANAGER -JUN-
    KING PRESIDENT -NOV-
    MILLER CLERK -JAN-
  3. SET运算符规则

    1. 每个查询列表中的表达式的个数和数据类型必须相匹配

    select后面的列的个数必须要一致:

    select empno,ename,deptno,sal from e1
    union all
    select empno,ename,deptno from e2; select empno,ename,deptno,sal from e1
    *
    第 行出现错误:
    ORA-: 查询块具有不正确的结果列数 select empno,ename,deptno,sal from e1
    union all
    select empno,ename,deptno,null from e2 null是可以的
    数据类型必须一致: select empno,ename,deptno,sal from e1
    union all
    select empno,ename,deptno,'abc' from e2 第 行出现错误:
    ORA-: 表达式必须具有与对应表达式相同的数据类型

    2. 可以使用括号来改变执行的顺序

    select * from e1
    intersect
    select * from e2
    union
    select * from e2; ENAME EMPNO SAL DEPTNO
    ------ ----- ----- ------
    ADAMS
    ALLEN
    BLAKE
    FORD
    JAMES
    JONES
    MARTIN
    SCOTT
    SMITH
    TURNER
    WARD 已选择11行。 select * from e1
    intersect
    (select * from e2
    union
    select * from e2); ENAME EMPNO SAL DEPTNO
    ------ ----- ----- ------
    ADAMS
    FORD
    JONES
    SCOTT
    SMITH

    3. ORDER BY 子句的使用:

    除了union all之外,其他的集合运算符都要按照第一个查询的第一列,进行升序

    只可以在语句的最后出现:

    select empno,ename,sal,deptno from e2
    union
    select empno,ename,sal,deptno from e2
    order by ename desc; EMPNO ENAME SAL DEPTNO
    ----- ------ ----- ------
    WARD
    TURNER
    SMITH
    SCOTT
    MARTIN
    JONES
    JAMES
    FORD
    BLAKE
    ALLEN
    ADAMS

    可以使用第一个查询语句的列名、别名、或位置(号)

    select empno,ename name1,sal,deptno from e2
    union
    select empno,ename name2,sal,deptno from e2
    order by name1 desc; EMPNO NAME1 SAL DEPTNO
    ----- ---------- ----- ------
    WARD
    TURNER
    SMITH
    SCOTT
    MARTIN
    JONES
    JAMES
    FORD
    BLAKE
    ALLEN
    ADAMS 已选择11行。 select empno,ename name1,sal,deptno from e2
    union
    select empno,ename name2,sal,deptno from e2
    order by name2 desc; order by name2 desc
    *
    第 行出现错误:
    ORA-: "NAME2": 标识符无效 select empno,ename,sal,deptno from e2
    union
    select empno,to_char(sal) salary, null,deptno from e2
    order by ; EMPNO ENAME SAL DEPTNO
    ----- ------ ----- ------ ADAMS
    ALLEN
    BLAKE
    FORD
    JAMES
    JONES
    MARTIN
    SCOTT
    SMITH
    TURNER
    WARD

    第一个查询语句的列名出现在结果中

    select empno,to_char(sal) salary, null,deptno from e2
    union
    select empno,ename,sal,deptno from e2
    order by
    / EMPNO SALARY NULL DEPTNO
    ----- ---------------------------------------- ---------- ------ ADAMS
    ALLEN
    BLAKE
    FORD
    JAMES
    JONES
    MARTIN
    SCOTT
    SMITH
    TURNER
    WARD

    查询语句的匹配:个数和数据类型的匹配

    select empno,ename,sal,deptno from e1
    union
    select ,to_char(sal),null, from e2; EMPNO ENAME SAL DEPTNO
    ----- ------ ----- ------ SMITH
    JONES
    CLARK
    SCOTT
    KING
    ADAMS
    FORD
    MILLER
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