Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 8), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤) and N (≤) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:
5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24
Sample Output:
24
这种纯暴力都能过,
虽然数据结构书上有一种找过半的那个算法,
在但是麻烦呐。
1 #include <bits/stdc++.h> 2 3 using namespace std; 4 int x; 5 int an[(2<<24) + 10]; 6 int n,m; 7 8 int main(){ 9 scanf("%d%d", &n,&m); 10 for(int i = 0; i < m; i ++){ 11 for(int j = 0 ; j < n; j++){ 12 scanf("%d", &x); 13 an[x]++; 14 } 15 } 16 for(int i = 0; i <= (2<<24); i++){ 17 if(an[i] > (n*m)/2){ 18 printf("%d\n", i); 19 return 0; 20 } 21 } 22 return 0; 23 }